with 4 drives we get a total of 256 possible sets. So algorithm automatically chooses 64 sets, which is *16* 64 = 1024* drives in total.

- *If total number of nodes are of odd number then GCD algorithm provides affinity towards odd number erasure sets to provide for uniform distribution across nodes*. This is to ensure that same number of drives are pariticipating in any erasure set. For example if you have 2 nodes with 180 drives then GCD is 15 but this would lead to uneven distribution,...

                          number:
                            maximum: 65535
                            minimum: 1
                            type: integer
                        required:
                        - number
                        type: object
                      type: array
                      x-kubernetes-list-map-keys:
                      - number
                      x-kubernetes-list-type: map

                            "type": "number",
                            "description": "The price must be greater than zero",
                        },
                        "tax": IsDict(
                            {
                                "title": "Tax",
                                "anyOf": [{"type": "number"}, {"type": "null"}],
                            }
                        )

     * @param {string} options.prefix - Prefix to use for data attributes.
     * @param {number} options.startDelay - Delay before animation, in ms.
     * @param {number} options.typeDelay - Delay between each typed character, in ms.
     * @param {number} options.lineDelay - Delay between each line, in ms.
     * @param {number} options.progressLength - Number of characters displayed as progress bar.

- **MinIO creates erasure-coding sets of _2_ to _16_ drives per set.  The number of drives you provide in total must be a multiple of one of those numbers.**
- **MinIO chooses the largest EC set size which divides into the total number of drives or total number of nodes given - making sure to keep the uniform distribution i.e each node participates equal number of drives per set**.

	} else {
		for i := 0; i < len(unMarshalXLMeta.Parts); i++ {
			if unMarshalXLMeta.Parts[i].Number != jsoniterXLMeta.Parts[i].Number {
				t.Errorf("Expected the number of part %d to be \"%d\", got \"%d\".", i+1, unMarshalXLMeta.Parts[i].Number, jsoniterXLMeta.Parts[i].Number)
			}
			if unMarshalXLMeta.Parts[i].Size != jsoniterXLMeta.Parts[i].Size {

    Ordering<Number> numbers = Ordering.explicit((Number) 1);
    Ordering<Integer> integers = Ordering.explicit(1);

    // Like by like equals like
    Ordering<Number> unusedA = numbers.compound(numbers);

    // The compound takes the more specific type of the two, regardless of order

    Ordering<Number> unusedB = numbers.compound(objects);
    Ordering<Number> unusedC = objects.compound(numbers);

    Ordering<Number> numbers = Ordering.explicit((Number) 1);
    Ordering<Integer> integers = Ordering.explicit(1);

    // Like by like equals like
    Ordering<Number> unusedA = numbers.compound(numbers);

    // The compound takes the more specific type of the two, regardless of order

    Ordering<Number> unusedB = numbers.compound(objects);
    Ordering<Number> unusedC = objects.compound(numbers);

	if err != nil {
		b.Fatal(err)
	}

	// get text data generated for number of bytes equal to object size.
	textData := generateBytesData(objSize)
	// generate md5sum for the generated data.
	// md5sum of the data to written is required as input for PutObject.

	md5hex := getMD5Hash(textData)
	sha256hex := ""

	// benchmark utility which helps obtain number of allocations and bytes allocated per ops.
	b.ReportAllocs()

      }
      return array;
    }

    /** Number of bits */
    long bitSize() {
      return (long) data.length() * Long.SIZE;
    }

    /**
     * Number of set bits (1s).
     *
     * <p>Note that because of concurrent set calls and uses of atomics, this bitCount is a (very)
     * close *estimate* of the actual number of bits set. It's not possible to do better than an