public void testConcat_overflow_negative() {
    int dim1 = 1 << 16;
    int dim2 = 1 << 15;
    assertThat(dim1 * dim2).isLessThan(0);
    testConcatOverflow(dim1, dim2);
  }

  @GwtIncompatible // different overflow behavior; could probably be made to work by using ~~
  public void testConcat_overflow_nonNegative() {
    int dim1 = 1 << 16;
    int dim2 = 1 << 16;
    assertThat(dim1 * dim2).isAtLeast(0);

    int last = 0;
    for (int shards = 2; shards <= MAX_SHARDS; shards++) {
      int chosen = Hashing.consistentHash(h, shards);
      if (chosen != last) {
        map.incrementAndGet(shards);
        last = chosen;
      }
    }
  }

  private static final int ITERS = 10000;
  private static final int MAX_SHARDS = 500;

        deskey( key, false, decryptKeys );
    }

    // Turn an 8-byte key into internal keys.
    private void deskey( byte[] keyBlock, boolean encrypting, int[] KnL ) {

        int i, j, l, m, n;
        int[] pc1m = new int[56];
        int[] pcr  = new int[56];
        int[] kn   = new int[32];

        for ( j = 0; j < 56; ++j )  {
            l       = pc1[j];
            m       = l & 07;

    assertEquals(1, (int) enumer.nextElement());
    assertTrue(enumer.hasMoreElements());
    assertEquals(2, (int) enumer.nextElement());
    assertTrue(enumer.hasMoreElements());
    assertEquals(3, (int) enumer.nextElement());
    assertFalse(enumer.hasMoreElements());
  }

  private static Enumeration<Integer> enumerate(int... ints) {

    /*
     * This trick allows us to avoid having separate states for "first four ints" and "all other
     * four int chunks."  The state we want after the first four bytes is
     *
     * crc0 = ~int0
     * crc1 = int1
     * crc2 = int2
     * crc3 = int3
     *
     * ...so we set crc0 so that computeForWord(crc0) = -1 and xoring it with the first int

    assertEquals(1, (int) enumer.nextElement());
    assertTrue(enumer.hasMoreElements());
    assertEquals(2, (int) enumer.nextElement());
    assertTrue(enumer.hasMoreElements());
    assertEquals(3, (int) enumer.nextElement());
    assertFalse(enumer.hasMoreElements());
  }

  private static Enumeration<Integer> enumerate(int... ints) {

  public void testConcat_overflow_negative() {
    int dim1 = 1 << 16;
    int dim2 = 1 << 15;
    assertThat(dim1 * dim2).isLessThan(0);
    testConcatOverflow(dim1, dim2);
  }

  @GwtIncompatible // different overflow behavior; could probably be made to work by using ~~
  public void testConcat_overflow_nonNegative() {
    int dim1 = 1 << 16;
    int dim2 = 1 << 16;
    assertThat(dim1 * dim2).isAtLeast(0);

  }

  /** Returns a -1 if unable to parse */
  private static int tryParseDecimal(String string, int start, int end) {
    int decimal = 0;
    final int max = Integer.MAX_VALUE / 10; // for int overflow detection
    for (int i = start; i < end; i++) {
      if (decimal > max) {
        return -1;
      }
      decimal *= 10;
      int digit = Character.digit(string.charAt(i), 10);
      if (digit < 0) {

      return delegate.add(object);
    }
    int[] entries = requireEntries();
    @Nullable Object[] elements = requireElements();

    int newEntryIndex = this.size; // current size, and pointer to the entry to be appended
    int newSize = newEntryIndex + 1;
    int hash = smearedHash(object);
    int mask = hashTableMask();
    int tableIndex = hash & mask;
    int next = CompactHashing.tableGet(requireTable(), tableIndex);

   */
  Hasher newHasher(int expectedInputSize);

  /**
   * Shortcut for {@code newHasher().putInt(input).hash()}; returns the hash code for the given
   * {@code int} value, interpreted in little-endian byte order. The implementation <i>might</i>
   * perform better than its longhand equivalent, but should not perform worse.
   *
   * @since 12.0
   */
  HashCode hashInt(int input);

  /**