NbtAddress nbtAddress3 = new NbtAddress(mockName3, 0xC0A80102, false, NbtAddress.H_NODE); // Different address

        assertTrue(nbtAddress1.equals(nbtAddress2)); // Should be true as only address is compared
        assertFalse(nbtAddress1.equals(nbtAddress3));
        assertFalse(nbtAddress1.equals(null));
        assertFalse(nbtAddress1.equals("some string"));
    }

    @Test
    void testToString() {

        return new ExceptionSummary(null, message, null, children);
    }

    private ExceptionSummary handle(ModelProblem problem, String projectId) {
        if (ModelProblem.Severity.ERROR.compareTo(problem.getSeverity()) >= 0) {
            String message = problem.getMessage();

            String location = ModelProblemUtils.formatLocation(problem, projectId);

            if (!location.isEmpty()) {

   * @param left the map to treat as the "left" map for purposes of comparison
   * @param right the map to treat as the "right" map for purposes of comparison
   * @param valueEquivalence the equivalence relationship to use to compare values
   * @return the difference between the two maps
   * @since 10.0
   */
  public static <K extends @Nullable Object, V extends @Nullable Object>
      MapDifference<K, V> difference(

   * @param left the map to treat as the "left" map for purposes of comparison
   * @param right the map to treat as the "right" map for purposes of comparison
   * @param valueEquivalence the equivalence relationship to use to compare values
   * @return the difference between the two maps
   * @since 10.0
   */
  public static <K extends @Nullable Object, V extends @Nullable Object>
      MapDifference<K, V> difference(

    }
  }

  /**
   * Returns an immutable list containing the given elements, sorted according to their natural
   * order. The sorting algorithm used is stable, so elements that compare as equal will stay in the
   * order in which they appear in the input.
   *
   * <p>If your data has no duplicates, or you wish to deduplicate elements, use {@code

          castOrCopyToList(mapGenerator.order(castOrCopyToList(mapGenerator.getSampleElements(5))));
      sort(
          insertionOrder,
          new Comparator<V>() {
            @Override
            public int compare(V left, V right) {
              // The indexes are small enough for the subtraction trick to be safe.
              return indexOfEntryWithValue(left) - indexOfEntryWithValue(right);
            }

      Comparator<IndexedIterator<T>> heapComparator =
          (o1, o2) ->
              ComparisonChain.start()
                  .compare(o1.iterator.peek(), o2.iterator.peek(), itemComparator)
                  // When elements are equal, use insertion order to maintain stability
                  .compare(o1.index, o2.index)
                  .result();

      queue = new PriorityQueue<>(2, heapComparator);

  interface Y {}

  static class A implements X, Y {}

  static class B implements X, Y {}

  /**
   * This test passes if the {@code concat(…).filter(…).filter(…)} statement at the end compiles.
   * That statement compiles only if {@link FluentIterable#concat concat(aIterable, bIterable)}
   * returns a {@link FluentIterable} of elements of an anonymous type whose supertypes are the <a

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