* byte-based hashcode. Otherwise it returns {@link HashCode#asBytes}. Do <i>not</i> mutate this
   * array or else you will break the immutability contract of {@code HashCode}.
   */
  byte[] getBytesInternal() {
    return asBytes();
  }

  /**
   * Returns whether this {@code HashCode} and that {@code HashCode} have the same value, given that

   * byte-based hashcode. Otherwise it returns {@link HashCode#asBytes}. Do <i>not</i> mutate this
   * array or else you will break the immutability contract of {@code HashCode}.
   */
  byte[] getBytesInternal() {
    return asBytes();
  }

  /**
   * Returns whether this {@code HashCode} and that {@code HashCode} have the same value, given that

      for (int index = 0; index < size; index++) {
        sum += array[index].hashCode();
      }
    }
    return sum;
  }

  @Benchmark
  int arrayIndexedLength(int reps) {
    int sum = 0;
    for (int i = 0; i < reps; i++) {
      for (int index = 0; index < array.length; index++) {
        sum += array[index].hashCode();
      }
    }
    return sum;
  }

  @Benchmark

      dummy += Objects.hashCode(S0, S1, S2, S3);
    }
    return dummy;
  }

  @Benchmark
  int hashString_5(int reps) {
    int dummy = 0;
    for (int i = 0; i < reps; i++) {
      dummy += Objects.hashCode(S0, S1, S2, S3, S4);
    }
    return dummy;
  }

  @Benchmark
  int hashMixed_5(int reps) {
    int dummy = 0;
    for (int i = 0; i < reps; i++) {
      dummy += Objects.hashCode(I2, S1, D1, S2, I0);

    }

    @Override
    public int hashCode() {
        int result = containingType.hashCode();
        result = 31 * result + propertyName.hashCode();
        result = 31 * result + methodName.hashCode();
        result = 31 * result + methodDescriptor.hashCode();
        result = 31 * result + replacedAccessors.hashCode();
        return result;
    }

    @Override

    int expectedHashCode = 0;
    for (E element : getSampleElements()) {
      expectedHashCode += ((element == null) ? 0 : element.hashCode());
    }
    assertEquals(
        "A Set's hashCode() should be the sum of those of its elements.",
        expectedHashCode,
        getSet().hashCode());
  }

  @CollectionSize.Require(absent = CollectionSize.ZERO)
  @CollectionFeature.Require(ALLOWS_NULL_VALUES)

      assertErrorMessage(
          e,
          "the Object#hashCode ("
              + a.hashCode()
              + ") of "
              + a
              + " [group 1, item 1] must be equal to the Object#hashCode ("
              + b.hashCode()
              + ") of "
              + b);
      return;
    }
    fail("Should get invalid hashCode error");
  }

  public void testNullEqualityGroup() {

      equalsNonHost(other)
  }

  override fun hashCode(): Int {
    var result = 17
    result = 31 * result + url.hashCode()
    result = 31 * result + dns.hashCode()
    result = 31 * result + proxyAuthenticator.hashCode()
    result = 31 * result + protocols.hashCode()
    result = 31 * result + connectionSpecs.hashCode()
    result = 31 * result + proxySelector.hashCode()
    result = 31 * result + Objects.hashCode(proxy)

    Random random = new Random(7);
    List<HashCode> hashCodes = Lists.newArrayList();
    for (int i = 0; i < 10; i++) {
      hashCodes.add(HashCode.fromLong(random.nextLong()));
    }
    HashCode hashCode1 = Hashing.combineOrdered(hashCodes);
    Collections.shuffle(hashCodes, random);
    HashCode hashCode2 = Hashing.combineOrdered(hashCodes);

    assertFalse(hashCode1.equals(hashCode2));
  }

   * Arrays#hashCode(Object[])}. Note that array arguments to this method, with the exception of a
   * single Object array, do not get any special handling; their hash codes are based on identity
   * and not contents.
   *
   * <p>This is useful for implementing {@link Object#hashCode()}. For example, in an object that