.post(jsonRequestBody)
        .build();

    try (Response response = client.newCall(request).execute()) {
      if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);

      System.out.println(response.body().string());
    }
  }

  public static void main(String... args) throws Exception {
    new RequestBodyCompression().run();
  }

  }

  @AfterExperiment
  void tearDown() {
    double req = requests.get();
    double hit = req - misses.get();

    // Currently, this is going into /dev/null, but I'll fix that
    System.out.println("hit rate: " + hit / req);
  }

  // for proper distributions later:
  // import JSci.maths.statistics.ProbabilityDistribution;
  // int key = (int) dist.inverse(random.nextDouble());

        return protwordsService.getProtwordsFile(form.dictId)
                .map(file -> asStream(new File(file.getPath()).getName()).contentTypeOctetStream().stream(out -> {
                    file.writeOut(out);
                })).orElseGet(() -> {
                    throwValidationError(messages -> messages.addErrorsFailedToDownloadProtwordsFile(GLOBAL),

    /**
     * The media-type multipart/form-data follows the rules of all multipart MIME data streams as
     * outlined in RFC 2046. In forms, there are a series of fields to be supplied by the user who
     * fills out the form. Each field has a name. Within a given form, the names are unique.
     */
    @JvmField
    val FORM = "multipart/form-data".toMediaType()

sleep 30

./mc ls -r --versions minio1/newbucket >/tmp/minio1.txt
./mc ls -r --versions minio2/newbucket >/tmp/minio2.txt

out=$(diff -qpruN /tmp/minio1.txt /tmp/minio2.txt)
ret=$?
if [ $ret -ne 0 ]; then
	echo "BUG: expected no missing entries after replication resync: $out"
	exit 1

				peersLogOnceIf(ctx, err, "event: Encode failed")
				continue
			}
			out <- grid.NewBytesWithCopyOf(buf.Bytes())
		}
	}
}

// TraceHandler sends http trace messages back to peer rest client
func (s *peerRESTServer) TraceHandler(ctx context.Context, payload []byte, _ <-chan []byte, out chan<- []byte) *grid.RemoteErr {
	var traceOpts madmin.ServiceTraceOpts
	err := json.Unmarshal(payload, &traceOpts)

 * limitations under the License.
 */
package okhttp3

import java.io.IOException
import java.util.concurrent.TimeUnit

/**
 * Observes, modifies, and potentially short-circuits requests going out and the corresponding
 * responses coming back in. Typically interceptors add, remove, or transform headers on the request
 * or response.
 *

 |
 |                 -it /path/to/installation/toolchains.xml
 |
 | The sections in this sample file are intended to give you a running start at
 | getting the most out of your Maven installation.
 |-->
<toolchains xmlns="http://maven.apache.org/TOOLCHAINS/1.1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

        validate(form, messages -> {}, this::asListHtml);
        verifyTokenKeep(this::asListHtml);
        return asStream(file.getName()).contentTypeOctetStream().stream(out -> {
            try (FileInputStream fis = new FileInputStream(file)) {
                out.write(fis);
            }
        });
    }

    @Execute
    @Secured({ ROLE })
    public HtmlResponse delete(final FileAccessForm form) {

    a >>= aTwos; // divide out all 2s
    int bTwos = Long.numberOfTrailingZeros(b);
    b >>= bTwos; // divide out all 2s
    while (a != b) { // both a, b are odd
      // The key to the binary GCD algorithm is as follows:
      // Both a and b are odd. Assume a > b; then gcd(a - b, b) = gcd(a, b).
      // But in gcd(a - b, b), a - b is even and b is odd, so we can divide out powers of two.