int shift2 = shift1 + 10;
    loader.setValuePrefix(shift2);
    // fill with new data - has to live for 20 ms more
    for (int i = 0; i < 10; i++) {
      cache.invalidate(keyPrefix + i);
      assertWithMessage("key: %s%s", keyPrefix, i)
          .that(cache.getUnchecked(keyPrefix + i))
          .isEqualTo(i + shift2);
    }

      sink.writeByte(0b1000_0000 or lengthByteCount)
      for (shift in (lengthByteCount - 1) * 8 downTo 0 step 8) {
        sink.writeByte((length shr shift).toInt())
      }
    }

    // Write the payload.
    sink.writeAll(content)
  }

  /**
   * Execute [block] with a new namespace for type hints. Type hints from the enclosing type are no
   * longer usable by the current type's members.
   */

## Overview

MinIO implements an S3 extension to perform multiple concurrent fan-out upload operations. A perfect use case scenario for performing fan-out operations of incoming TSB (Time Shift Buffer's). TSBs are a method of facilitating time-shifted playback of television signaling, and media content.

do
    case $1 in
      --help) ARGV="$ARGV -h"; shift;;
      --*=*) properties="$properties -Dfess.${1#--}"
           shift 1
           ;;
      --*) [ $# -le 1 ] && {
                echo "Option requires an argument: '$1'."
                shift
                continue
            }
           properties="$properties -Dfess.${1#--}=$2"
           shift 2
           ;;
      *) ARGV="$ARGV $1" ; shift

	// a rune/ScanToken value for them - ugly but simple.
	LSH          ScanToken = -1000 - iota // << Left shift.
	RSH                                   // >> Logical right shift.
	ARR                                   // -> Used on ARM for shift type 3, arithmetic right shift.
	ROT                                   // @> Used on ARM for shift type 4, rotate right.
	Include                               // included file started here

	{"3%0", "modulo by zero"},
	{"(1<<63)%0", "modulo of value with high bit set"},
	{"3<<-4", "negative left shift count"},
	{"3<<(1<<63)", "negative left shift count"},
	{"3>>-4", "negative right shift count"},
	{"3>>(1<<63)", "negative right shift count"},
	{"(1<<63)>>2", "right shift of value with high bit set"},
	{"(1<<62)>>2", ""},
	{`'\x80'`, "illegal UTF-8 encoding for character constant"},

	MOVB	R0>>8, R2          // ERROR "illegal shift"
	MOVH	R0<<16, R2         // ERROR "illegal shift"
	MOVBS	R0->8, R2          // ERROR "illegal shift"
	MOVHS	R0<<24, R2         // ERROR "illegal shift"
	MOVBU	R0->24, R2         // ERROR "illegal shift"
	MOVHU	R0@>1, R2          // ERROR "illegal shift"
	XTAB	R0>>8, R2          // ERROR "illegal shift"
	XTAH	R0<<16, R2         // ERROR "illegal shift"

    // So we can ignore the bottom 11, except for rounding. We can unsigned-shift right 1, aka
    // unsigned-divide by 2, and convert that. Then we'll get exactly half of the desired double
    // value. But in the specific case where the bottom two bits of the original number are 01, we
    // want to replace that with 1 in the shifted value for correct rounding.
    return (double) ((value >>> 1) | (value & 1)) * 2.0;
  }

      sqrt0 = sqrtApproxWithDoubles(x);
    } else {
      int shift = (log2 - DoubleUtils.SIGNIFICAND_BITS) & ~1; // even!
      /*
       * We have that x / 2^shift < 2^54. Our initial approximation to sqrtFloor(x) will be
       * 2^(shift/2) * sqrtApproxWithDoubles(x / 2^shift).
       */
      sqrt0 = sqrtApproxWithDoubles(x.shiftRight(shift)).shiftLeft(shift >> 1);
    }

     * top SIGNIFICAND_BITS + 1.
     *
     * It helps to consider the real number signif = absX * 2^(SIGNIFICAND_BITS - exponent).
     */
    int shift = exponent - SIGNIFICAND_BITS - 1;
    long twiceSignifFloor = absX.shiftRight(shift).longValue();
    long signifFloor = twiceSignifFloor >> 1;
    signifFloor &= SIGNIFICAND_MASK; // remove the implied bit

    /*