* have been removed.
   *
   * <p><b>Warning:</b> Typical uses of the resulting iterator may produce an infinite loop. You
   * should use an explicit {@code break} or be certain that you will eventually remove all the
   * elements.
   *
   * <p>To cycle over the elements {@code n} times, use the following: {@code
   * Iterables.concat(Collections.nCopies(n, Arrays.asList(elements)))}
   *

    E[] elements = createSamplesArray();
    E duplicate = elements[(elements.length / 2) - 1];
    elements[(elements.length / 2) + 1] = duplicate;
    return new ArrayWithDuplicate<>(elements, duplicate);
  }

  // Helper methods to improve readability of derived classes

  protected int getNumElements() {
    return getSubjectGenerator().getCollectionSize().getNumElements();
  }

      return unfiltered.add(element, occurrences);
    }

    @Override
    public int remove(@CheckForNull Object element, int occurrences) {
      checkNonnegative(occurrences, "occurrences");
      if (occurrences == 0) {
        return count(element);
      } else {
        return contains(element) ? unfiltered.remove(element, occurrences) : 0;
      }

     */
    @Input
    boolean isEnabled();

    /**
     * Sets element for the rule.
     *
     * @param element Element
     */
    void setElement(String element);

    /**
     * Gets the element for the rule as defined by

    }

    @Override
    public boolean add(@ParametricNullness E element) {
      checkArgument(predicate.apply(element));
      return unfiltered.add(element);
    }

    @Override
    public boolean addAll(Collection<? extends E> collection) {
      for (E element : collection) {
        checkArgument(predicate.apply(element));
      }
      return unfiltered.addAll(collection);
    }

 * according to when the first occurrence of the element was added. When the multiset contains
 * multiple instances of an element, those instances are consecutive in the iteration order. If all
 * occurrences of an element are removed, after which that element is added to the multiset, the
 * element will appear at the end of the iteration.
 *

    HierarchicalElement getParent();

    /**
     * Returns the child elements, or the empty set if there are no child elements.
     *
     * @return The child elements, or the empty set if there are no child elements.
     * @since 1.0-milestone-5
     */
    DomainObjectSet<? extends HierarchicalElement> getChildren();

    public IsolatedList(ImmutableList<Isolatable<?>> elements) {
        super(elements);
    }

    @Override
    public ValueSnapshot asSnapshot() {
        if (elements.isEmpty()) {
            return ListValueSnapshot.EMPTY;
        }
        ImmutableList.Builder<ValueSnapshot> builder = ImmutableList.builderWithExpectedSize(elements.size());
        for (Isolatable<?> element : elements) {
            builder.add(element.asSnapshot());

 * elements FIFO (first-in-first-out). The head of the queue is that element that has been
 * on the queue the longest time. The tail of the queue is that element that has been on
 * the queue the shortest time. New elements are inserted at the tail of the queue, and the queue
 * retrieval operations obtain elements at the head of the queue.
 *

/**
 * A non-blocking queue which automatically evicts elements from the head of the queue when
 * attempting to add new elements onto the queue and it is full. This queue orders elements FIFO
 * (first-in-first-out). This data structure is logically equivalent to a circular buffer (i.e.,
 * cyclic buffer or ring buffer).
 *
 * <p>An evicting queue must be configured with a maximum size. Each time an element is added to a