}

func ExampleDeleteFunc() {
	m := map[string]int{
		"one":   1,
		"two":   2,
		"three": 3,
		"four":  4,
	}
	maps.DeleteFunc(m, func(k string, v int) bool {
		return v%2 != 0 // delete odd values
	})
	fmt.Println(m)
	// Output:
	// map[four:4 two:2]
}

func ExampleEqual() {
	m1 := map[int]string{
		1:    "one",
		10:   "Ten",
		1000: "THOUSAND",
	}
	m2 := map[int]string{

	extra := uint(-dexp2)
	extraMask := uint32(1<<extra - 1)

	di, dfrac := di>>extra, di&extraMask
	roundUp := false
	if exact {
		// If we computed an exact product, d + 1/2
		// should round to d+1 if 'd' is odd.
		roundUp = dfrac > 1<<(extra-1) ||
			(dfrac == 1<<(extra-1) && !d0) ||
			(dfrac == 1<<(extra-1) && d0 && di&1 == 1)
	} else {
		// otherwise, d+1/2 always rounds up because
		// we truncated below.

drives we get a total of 128 possible sets, with 4 drives we get a total of 256 possible sets. So algorithm automatically chooses 64 sets, which is *16* 64 = 1024* drives in total.

- *If total number of nodes are of odd number then GCD algorithm provides affinity towards odd number erasure sets to provide for uniform distribution across nodes*. This is to ensure that same number of drives are pariticipating in any erasure set. For example if you have 2 nodes with 180 drives then GCD is 15 but...

		if b >= 2 {
			bytes[0] |= 3 << (b - 2)
		} else {
			// Here b==1, because b cannot be zero.
			bytes[0] |= 1
			if len(bytes) > 1 {
				bytes[1] |= 0x80
			}
		}
		// Make the value odd since an even number this large certainly isn't prime.
		bytes[len(bytes)-1] |= 1

		p.SetBytes(bytes)
		if p.ProbablyPrime(20) {
			return p, nil
		}
	}
}

	}
}

// ModSqrt sets z to a square root of x mod p if such a square root exists, and
// returns z. The modulus p must be an odd prime. If x is not a square mod p,
// ModSqrt leaves z unchanged and returns nil. This function panics if p is
// not an odd integer, its behavior is undefined if p is odd but not prime.
func (z *Int) ModSqrt(x, p *Int) *Int {
	switch Jacobi(x, p) {
	case -1:
		return nil // x is not a square mod p

 * not wrapped in {@code ExecutionException}. For just a normal failure, use {@link
 * SettableFuture}).
 *
 * <p>Useful for testing the behavior of Future utilities against odd futures.
 *
 * @author Anthony Zana
 */
@GwtCompatible
final class UncheckedThrowingFuture<V> extends AbstractFuture<V> {

  public static <V> ListenableFuture<V> throwingError(Error error) {

	// 386:"IMUL3L\t[$]678152731",-"ROLL",-"DIVQ"
	// arm64:"MOVD\t[$]-8737931403336103397","MUL",-"ROR",-"DIV"
	// arm:"MUL","CMP\t[$]226050910",-".*udiv"
	// ppc64x:"MULLD",-"ROTL"
	odd := n%19 == 0

	return even, odd
}

func Divisible(n int) (bool, bool) {
	// amd64:"IMULQ","ADD","ROLQ\t[$]63",-"DIVQ"
	// 386:"IMUL3L\t[$]-1431655765","ADDL\t[$]715827882","ROLL\t[$]31",-"DIVQ"

    int bTwos = Integer.numberOfTrailingZeros(b);
    b >>= bTwos; // divide out all 2s
    while (a != b) { // both a, b are odd
      // The key to the binary GCD algorithm is as follows:
      // Both a and b are odd. Assume a > b; then gcd(a - b, b) = gcd(a, b).
      // But in gcd(a - b, b), a - b is even and b is odd, so we can divide out powers of two.

      // We bend over backwards to avoid branching, adapting a technique from

	}
}

func TestSplitComponentLog(t *testing.T) {
	cases := []struct {
		input      string
		log        string
		components []string
	}{
		{"info", "info", nil},
		// A bit odd, but istio logging behaves this way so might as well be consistent
		{"info,warn", "warn", nil},
		{"info,misc:warn", "info", []string{"misc:warn"}},
		{"misc:warn,info", "info", []string{"misc:warn"}},

	// The constant-time implementation is adapted from Thomas Pornin's ecGFp5.
	//
	// https://github.com/pornin/ecgfp5/blob/82325b965/rust/src/field.rs#L337-L385

	// p = q*2^n + 1 with q odd -> q = 2^128 - 1 and n = 96
	// g^(2^n) = 1 -> g = 11 ^ q (where 11 is the smallest non-square)
	// GG[j] = g^(2^j) for j = 0 to n-1

	p224GGOnce.Do(func() {
		p224GG = new([96]fiat.P224Element)
		for i := range p224GG {