- Kube-proxy no longer falls back from ipvs mode to iptables mode if you ask it to do ipvs but the system is not correctly configured. Instead, it will just exit with an error. ([#111806](https://github.com/kubernetes/kubernetes/pull/111806), [@danwinship](https://github.com/danwinship)) [SIG Network]

- Fixed a bug that `kubectl create configmap` always returns zero exit code when failed. ([#101780](https://github.com/kubernetes/kubernetes/pull/101780), [@nak3](https://github.com/nak3)) [SIG CLI]

* Windows nodes on GCE use a known-working 1809 image rather than the latest 1809 image. ([#76722](https://github.com/kubernetes/kubernetes/pull/76722), [@pjh](https://github.com/pjh))
* kube-proxy: os exit when CleanupAndExit is set to true ([#76732](https://github.com/kubernetes/kubernetes/pull/76732), [@JieJhih](https://github.com/JieJhih))

    - **Known issues**

        - Shared PID namespace does not work properly.
          ([#207](https://github.com/kubernetes/community/pull/207#issuecomment-281870043))

        - Docker reports incorrect exit codes for containers.
          ([#41516](https://github.com/kubernetes/kubernetes/issues/41516))

- Docker 1.11.2

    - **Known issues**

        - Kernel crash with Aufs storage driver on Debian Jessie

- Kubectl port-forward service will now properly exit when the attached pod dies (#103526, @brianpursley) [SIG API Machinery]
- Kubelet: fixes a file descriptor leak in log rotation (#106382, @rphillips) [SIG Node]

After each loop iteration, u and v only get smaller, and at least one of // them shrinks by at least a factor of two. for { // If both u and v are odd, subtract the smaller from the larger. // If u = v, we need to subtract from v to hit the modified exit condition. if u.IsOdd() == yes && v.IsOdd() == yes { if v.cmpGeq(u) == no { u.sub(v) A.Add(C, &Modulus{nat: m}) B.Add(D, &Modulus{nat: a}) } else { v.sub(u) C.Add(A, &Modulus{nat: m}) D.Add(B, &Modulus{nat: a}) } } // Exactly one of u and v is now...

After each loop iteration, u and v only get smaller, and at least one of // them shrinks by at least a factor of two. for { // If both u and v are odd, subtract the smaller from the larger. // If u = v, we need to subtract from v to hit the modified exit condition. if u.IsOdd() == yes && v.IsOdd() == yes { if v.cmpGeq(u) == no { u.sub(v) A.Add(C, &Modulus{nat: m}) B.Add(D, &Modulus{nat: a}) } else { v.sub(u) C.Add(A, &Modulus{nat: m}) D.Add(B, &Modulus{nat: a}) } } // Exactly one of u and v is now...