* 1}, this method has the identical effect to {@link #add(Object)}. This method is functionally
   * equivalent (except in the case of overflow) to the call {@code
   * addAll(Collections.nCopies(element, occurrences))}, which would presumably perform much more
   * poorly.
   *

    }

  private fun gzip(data: ByteArray): Buffer {
    val buffer = Buffer()
    GzipSink(buffer).buffer().write(data).close()
    return buffer
  }

  /** Create a sufficiently large header set to overflow INITIAL_MAX_FRAME_SIZE bytes.  */
  private fun largeHeaders(): List<Header> {
    val nameValues = arrayOfNulls<String>(32)
    val chars = CharArray(512)
    var i = 0
    while (i < nameValues.size) {

      int adjust = size() - 1;
      for (int i = 0; i < axes.size(); i++) {
        adjust *= 31;
        adjust = ~~adjust;
        // in GWT, we have to deal with integer overflow carefully
      }
      int hash = 1;
      for (Set<E> axis : axes) {
        hash = 31 * hash + (size() / axis.size() * axis.hashCode());

        hash = ~~hash;
      }
      hash += adjust;

oLowerCase():null}function d(e){return((n(e)?e.ownerDocument:e.document)||window.document).documentElement}function h(e){return p(d(e)).left+u(e).scrollLeft}function m(e){return t(e).getComputedStyle(e)}function v(e){var t=m(e),n=t.overflow,r=t.overflowX,o=t.overflowY;return/auto|scroll|overlay|hidden/.test(n+o+r)}function y(e,n,o){void 0===o&&(o=!1);var i,a,f=r(n),c=r(n)&&function(e){var t=e.getBoundingClientRect(),n=s(t.width)/e.offsetWidth||1,r=s(t.height)/e.offsetHeight||1;return 1!==n||1!==...

      setFutureSuccess.set(false);
      cancellationSuccess.set(false);
      finalResults.clear();
    }
    executor.shutdown();
  }

  // In a previous implementation this would cause a stack overflow after ~2000 futures chained
  // together.  Now it should only be limited by available memory (and time)
  public void testSetFuture_stackOverflow() {
    SettableFuture<String> orig = SettableFuture.create();

      /*
       * It speeds things up considerably to unconditionally add count to totalCount here,
       * but that destroys failure atomicity in the case of count overflow. =(
       */
      int cmp = comparator.compare(e, getElement());
      if (cmp < 0) {
        AvlNode<E> initLeft = left;
        if (initLeft == null) {
          result[0] = 0;

    i = 1 << 30;
    assertFalse(MinMaxPriorityQueue.isEvenLevel(i - 2));
    assertTrue(MinMaxPriorityQueue.isEvenLevel(i - 1));
    assertTrue(MinMaxPriorityQueue.isEvenLevel(i));

    // 1 << 31 is negative because of overflow, 1 << 31 - 1 is positive
    // since isEvenLevel adds 1, we need to do - 2.
    assertTrue(MinMaxPriorityQueue.isEvenLevel((1 << 31) - 2));
    assertTrue(MinMaxPriorityQueue.isEvenLevel(Integer.MAX_VALUE - 1));

        void testLargeMidValue() {
            long largeMid = Long.MAX_VALUE;
            testMessage.setMid(largeMid);
            assertEquals(largeMid, testMessage.getMid());

            // HashCode should handle overflow correctly
            int hash = testMessage.hashCode();
            assertEquals((int) largeMid, hash);
        }

        @Test
        @DisplayName("Should handle negative status codes")

urn t?n[t]:n}function o(e){return'HTML'===e.nodeName?e:e.parentNode||e.host}function n(e){if(!e)return document.body;switch(e.nodeName){case'HTML':case'BODY':return e.ownerDocument.body;case'#document':return e.body;}var i=t(e),r=i.overflow,p=i.overflowX,s=i.overflowY;return /(auto|scroll|overlay)/.test(r+s+p)?e:n(o(e))}function i(e){return e&&e.referenceNode?e.referenceNode:e}function r(e){return 11===e?re:10===e?pe:re||pe}function p(e){if(!e)return document.documentElement;for(var o=r(10)?docu...

    return (byte) octet;
  }

  /** Returns a -1 if unable to parse */
  private static int tryParseDecimal(String string, int start, int end) {
    int decimal = 0;
    int max = Integer.MAX_VALUE / 10; // for int overflow detection
    for (int i = start; i < end; i++) {
      if (decimal > max) {
        return -1;
      }
      decimal *= 10;
      int digit = Character.digit(string.charAt(i), 10);
      if (digit < 0) {