CacheStats sum = two.plus(one);
    assertEquals(124, sum.requestCount());
    assertEquals(64, sum.hitCount());
    assertEquals(64.0 / 124, sum.hitRate());
    assertEquals(60, sum.missCount());
    assertEquals(60.0 / 124, sum.missRate());
    assertEquals(56, sum.loadSuccessCount());
    assertEquals(52, sum.loadExceptionCount());
    assertEquals(52.0 / 108, sum.loadExceptionRate());

        sum += array[index].hashCode();
      }
    }
    return sum;
  }

  @Benchmark
  int arrayFor(int reps) {
    int sum = 0;
    for (int i = 0; i < reps; i++) {
      for (Object value : array) {
        sum += value.hashCode();
      }
    }
    return sum;
  }

  @Benchmark
  int arrayListIndexed(int reps) {
    int sum = 0;
    for (int i = 0; i < reps; i++) {

    add(-1L);
  }

  /**
   * Returns the current sum. The returned value is NOT an atomic snapshot; invocation in
   * the absence of concurrent updates returns an accurate result, but concurrent updates that occur
   * while the sum is being calculated might not be incorporated.
   *
   * @return the sum
   */
  @Override
  public long sum() {
    long sum = base;
    Cell[] as = cells;
    if (as != null) {

  @Benchmark
  int hashMultiset(int reps) {
    int sum = 0;
    for (int i = 0; i < reps; i++) {
      for (Object value : hashMultiset) {
        sum += value.hashCode();
      }
    }
    return sum;
  }

  @Benchmark
  int linkedHashMultiset(int reps) {
    int sum = 0;
    for (int i = 0; i < reps; i++) {
      for (Object value : linkedHashMultiset) {
        sum += value.hashCode();
      }
    }

    int expectedHashCode = 0;
    for (E element : getSampleElements()) {
      expectedHashCode += ((element == null) ? 0 : element.hashCode());
    }
    assertEquals(
        "A Set's hashCode() should be the sum of those of its elements.",
        expectedHashCode,
        getSet().hashCode());
  }

  @CollectionSize.Require(absent = CollectionSize.ZERO)
  @CollectionFeature.Require(ALLOWS_NULL_VALUES)

    add(-1L);
  }

  /**
   * Returns the current sum. The returned value is NOT an atomic snapshot; invocation in
   * the absence of concurrent updates returns an accurate result, but concurrent updates that occur
   * while the sum is being calculated might not be incorporated.
   *
   * @return the sum
   */
  @Override
  public long sum() {
    long sum = base;
    Cell[] as = cells;
    if (as != null) {

                }
              }));
    }
    threadPool.shutdown();
    assertTrue(threadPool.awaitTermination(300, SECONDS));
    long sum = 0;
    for (Future<Long> f : futures) {
      sum += f.get();
    }
    assertEquals(sum, map.get(key));
  }

        sum += array[index].hashCode();
      }
    }
    return sum;
  }

  @Benchmark
  int arrayFor(int reps) {
    int sum = 0;
    for (int i = 0; i < reps; i++) {
      for (Object value : array) {
        sum += value.hashCode();
      }
    }
    return sum;
  }

  @Benchmark
  int arrayListIndexed(int reps) {
    int sum = 0;
    for (int i = 0; i < reps; i++) {

    CacheStats sum = two.plus(one);
    assertEquals(124, sum.requestCount());
    assertEquals(64, sum.hitCount());
    assertEquals(64.0 / 124, sum.hitRate());
    assertEquals(60, sum.missCount());
    assertEquals(60.0 / 124, sum.missRate());
    assertEquals(56, sum.loadSuccessCount());
    assertEquals(52, sum.loadExceptionCount());
    assertEquals(52.0 / 108, sum.loadExceptionRate());

 * Abstract interface for objects that can concurrently add longs.
 *
 * @author Louis Wasserman
 */
@ElementTypesAreNonnullByDefault
interface LongAddable {
  void increment();

  void add(long x);

  long sum();