assertEquals(0, removalListener.getCount());

    int shift2 = shift1 + 10;
    loader.setValuePrefix(shift2);
    // fill with new data - has to live for 20 ms more
    for (int i = 0; i < 10; i++) {
      cache.invalidate(keyPrefix + i);
      assertEquals(
          "key: " + keyPrefix + i, Integer.valueOf(i + shift2), cache.getUnchecked(keyPrefix + i));
    }

   */
  public static final byte CR = 13;

  /**
   * Shift Out: A control character indicating that the code combinations which follow shall be
   * interpreted as outside of the character set of the standard code table until a Shift In
   * character is reached.
   *
   * @since 8.0
   */
  public static final byte SO = 14;

  /**

        int remainingPowersOf2 = 32;
        do {
          int shift = min(remainingPowersOf2, Long.numberOfLeadingZeros(a));
          // shift is either the number of powers of 2 left to multiply a by, or the biggest shift
          // possible while keeping a in an unsigned long.
          a = UnsignedLongs.remainder(a << shift, m);
          remainingPowersOf2 -= shift;
        } while (remainingPowersOf2 > 0);
        return a;

    assertEquals(0, removalListener.getCount());

    int shift2 = shift1 + 10;
    loader.setValuePrefix(shift2);
    // fill with new data - has to live for 20 ms more
    for (int i = 0; i < 10; i++) {
      cache.invalidate(keyPrefix + i);
      assertEquals(
          "key: " + keyPrefix + i, Integer.valueOf(i + shift2), cache.getUnchecked(keyPrefix + i));
    }

        ImmutableMap.of(
            new IntegerDiv10(3), "three",
            new IntegerDiv10(20), "twenty",
            new IntegerDiv10(11), "eleven",
            new IntegerDiv10(35), "thirty five",
            new IntegerDiv10(12), "twelve");

    try {
      ImmutableSortedMap.copyOf(original);
      fail("Expected IllegalArgumentException");
    } catch (IllegalArgumentException expected) {
    }

             * little-endian. Long.numberOfTrailingZeros(diff) tells us the least significant
             * nonzero bit, and zeroing out the first three bits of L.nTZ gives us the shift to get
             * that least significant nonzero byte.
             */
            int n = Long.numberOfTrailingZeros(lw ^ rw) & ~0x7;

      sqrt0 = sqrtApproxWithDoubles(x);
    } else {
      int shift = (log2 - DoubleUtils.SIGNIFICAND_BITS) & ~1; // even!
      /*
       * We have that x / 2^shift < 2^54. Our initial approximation to sqrtFloor(x) will be
       * 2^(shift/2) * sqrtApproxWithDoubles(x / 2^shift).
       */
      sqrt0 = sqrtApproxWithDoubles(x.shiftRight(shift)).shiftLeft(shift >> 1);
    }

   */
  public static final byte CR = 13;

  /**
   * Shift Out: A control character indicating that the code combinations which follow shall be
   * interpreted as outside of the character set of the standard code table until a Shift In
   * character is reached.
   *
   * @since 8.0
   */
  public static final byte SO = 14;

  /**

        }
      }

      long buffer = 0;
      int shift = 0;
      for (; i < utf16Length; i++) {
        char c = input.charAt(i);
        if (c < 0x80) {
          buffer |= (long) c << shift;
          shift += 8;
          len++;
        } else if (c < 0x800) {
          buffer |= charToTwoUtf8Bytes(c) << shift;
          shift += 16;
          len += 2;

      if ((radix & (radix - 1)) == 0) {
        // Radix is a power of two so we can avoid division.
        int shift = Integer.numberOfTrailingZeros(radix);
        int mask = radix - 1;
        do {
          buf[--i] = Character.forDigit(((int) x) & mask, radix);
          x >>>= shift;
        } while (x != 0);
      } else {
        // Separate off the last digit using unsigned division. That will leave