if m.expMovingAvg == 0 {
		// Should address initial calculation and should be fine for resuming from 0
		m.expMovingAvg = float64(bytesSinceLastWindow) / duration.Seconds()
		return
	}

	increment := float64(bytesSinceLastWindow) / duration.Seconds()
	m.expMovingAvg = exponentialMovingAverage(beta, m.expMovingAvg, increment)
}

// exponentialMovingAverage calculates the exponential moving average

     * correct order—in order words, that it doesn't mix up big-endian and little-endian. The first
     * array has a smaller element at one index, and then the second array has a smaller element at
     * the next.
     */
    byte[] a0 = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 99, 15, 16, 17};
    byte[] b0 = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 99, 14, 15, 16, 17};

     * on an SMB server addressed by the <code>SmbFile</code> parameter. See
     * {@link jcifs.smb.SmbFile} for a detailed description and examples of
     * the smb URL syntax. If the second argument is <code>true</code>, then
     * bytes will be written to the end of the file rather than the beginning.
     *
     * @param file
     *            An <code>SmbFile</code> representing the file to write to

            bulkDelete.add(client.prepareDelete().setIndex(indexName).setId(docId));
        }
        bulkDelete.execute().actionGet(fessConfig.getIndexSearchTimeout());

        // Delete any remaining events beyond the search size limit (discard overflow)
        try {
            client.deleteByQuery(indexName, QueryBuilders.termQuery("hostname", hostname));
        } catch (final Exception e) {

        // Scenario 2: Command timeout
        CommandExecutionException timeout =
                new CommandExecutionException("Command execution timed out after 30 seconds", new RuntimeException("Timeout"));
        assertTrue(timeout.getMessage().contains("timed out"));
        assertNotNull(timeout.getCause());

        // Scenario 3: Permission denied

#### Ein „professioneller“ Angriff { #a-professional-attack }

Natürlich würden die Angreifer das alles nicht von Hand versuchen, sondern ein Programm dafür schreiben, möglicherweise mit Tausenden oder Millionen Tests pro Sekunde. Und würden jeweils nur einen zusätzlichen richtigen Buchstaben erhalten.

		// Run the data scanner in a loop
		for {
			runDataScanner(ctx, objAPI)
			duration := max(time.Duration(r.Float64()*float64(scannerCycle.Load())),
				// Make sure to sleep at least a second to avoid high CPU ticks.
				time.Second)
			time.Sleep(duration)
		}
	}()
}

func getCycleScanMode(currentCycle, bitrotStartCycle uint64, bitrotStartTime time.Time) madmin.HealScanMode {

import static com.google.common.collect.Iterators.peekingIterator;
import static java.nio.charset.StandardCharsets.UTF_8;
import static java.util.Objects.requireNonNull;
import static java.util.concurrent.TimeUnit.SECONDS;

import com.google.common.annotations.GwtIncompatible;
import com.google.common.annotations.J2ktIncompatible;
import com.google.common.base.CharMatcher;
import com.google.common.base.Defaults;

		// to avoid multiple pool leaders herding to update around the same
		// time.
		r := rand.New(rand.NewSource(time.Now().UnixNano()))
		randSleepFor := func() time.Duration {
			return 5*time.Second + time.Duration(float64(5*time.Second)*r.Float64())
		}

		timer := time.NewTimer(randSleepFor())
		defer timer.Stop()

		var (
			quit     bool
			traceMsg string

  }

  /**
   * Returns an unmodifiable view of the difference of two multisets. In the returned multiset, the
   * count of each element is the result of the <i>zero-truncated subtraction</i> of its count in
   * the second multiset from its count in the first multiset, with elements that would have a count
   * of 0 not included. The iteration order of the returned multiset matches that of the element set