Collector<T, A, R> collector, BiPredicate<? super R, ? super R> equivalence) {
    this.collector = checkNotNull(collector);
    this.equivalence = checkNotNull(equivalence);
  }

  /**
   * Different orderings for combining the elements of an input array, which must all produce the
   * same result.
   */
  @IgnoreJRERequirement // *should* be redundant with the one on CollectorTester
  enum CollectStrategy {

        return srcIndex - start;
    }

    @Override
    public int hashCode() {
        int result = name.hashCode();
        result += 65599 * hexCode;
        result += 65599 * srcHashCode; /* hashCode is different depending
                                        * on where it came from
                                        */
        if (scope != null && scope.length() != 0) {
            result += scope.hashCode();
        }

                 * so. We cannot just comment out this method and use readString of
                 * ServerMessageBlock.java because the arguments are different, however
                 * one might be able to reduce this.
                 */

                if (len > 0 && src[srcIndex + len - 1] == '\0') {
                    len--;
                }

     * repository. It is worth to point out that merging does not simply choose one of the input repositories and
     * discards the others but actually combines their possibly different policies.
     *
     * @param repositories The original repositories, may be {@code null}.
     * @return The effective repositories or {@code null} if the input was {@code null}.
     */

		if message == "You already own this bucket. Please select another name." {
			err = BucketAlreadyOwnedByYou{Bucket: bucket}
			break
		}
		if message == "Sorry, that name is not available. Please try a different one." {
			err = BucketAlreadyExists{Bucket: bucket}
			break
		}
		err = BucketNotEmpty{Bucket: bucket}
	}

	return err

	for _, len := range lengths {
		// randomish but deterministic data. No 0 or 255.
		for i := 0; i < len; i++ {
			a[i] = byte(1 + 31*i%254)
			b[i] = byte(1 + 31*i%254)
		}
		// data past the end is different
		for i := len; i <= n; i++ {
			a[i] = 8
			b[i] = 9
		}
		cmp := Compare(a[:len], b[:len])
		if cmp != 0 {
			t.Errorf(`CompareIdentical(%d) = %d`, len, cmp)
		}
		if len > 0 {

            assertEquals(expectedCause, e.getCause());
        }
    }

    public void test_multipleExceptions_differentStatusCodes() {
        // Test creating multiple exceptions with different status codes
        WebApiException exception1 = new WebApiException(400, "Bad Request");
        WebApiException exception2 = new WebApiException(401, "Unauthorized");

        community can discuss and debate whether this feature is actually the *best* way to address
        the real use case, or whether or not a different abstraction might be more appropriate.


        It's okay if you can't provide complete context on a use case. We understand if you are not
        able to discuss the full details of what you're working on.

    char[] charsB = new char[128];

    for (int i = 0; i < charsA.length; i++) {
      if (i < 100) {
        charsA[i] = 'a';
        charsB[i] = 'a';
      } else {
        // Both two-byte characters, but must be different
        charsA[i] = (char) (0x0180 + i);
        charsB[i] = (char) (0x0280 + i);
      }
    }

    String stringA = new String(charsA);
    String stringB = new String(charsB);

   * generalized escaping for characters.
   *
   * <p>Note that arrays returned by this method must not be modified once they have been returned.
   * However it is acceptable to return the same array multiple times (even for different input
   * characters).
   *
   * @param c the character to escape
   * @return the replacement characters, or {@code null} if no escaping was required
   */