Keep in mind that when using `Query` inside of `Annotated` you cannot use the `default` parameter for `Query`.

Instead, use the actual default value of the function parameter. Otherwise, it would be inconsistent.

For example, this is not allowed:

```Python
q: Annotated[str, Query(default="rick")] = "morty"
```

...because it's not clear if the default value should be `"rick"` or `"morty"`.

   * predicate)} and use the copy.
   *
   * <p><b>Warning:</b> {@code predicate} must be <i>consistent with equals</i>, as documented at
   * {@link Predicate#apply}. Do not provide a predicate such as {@code
   * Predicates.instanceOf(ArrayList.class)}, which is inconsistent with equals. (See {@link
   * Iterables#filter(Iterable, Class)} for related functionality.)
   *

		tops = tops[:0]
		var topSig xlMetaV2VersionHeader
		consistent := true // Are all signatures consistent (shortcut)
		for _, vers := range versions {
			if len(vers) == 0 {
				consistent = false
				continue
			}
			ver := vers[0]
			if len(tops) == 0 {
				consistent = true
				topSig = ver.header
			} else {
				consistent = consistent && ver.header == topSig
			}
			tops = append(tops, vers[0])

        }
        checkArgument(
            fromParameterizedType.getRawType().equals(toParameterizedType.getRawType()),
            "Inconsistent raw type: %s vs. %s",
            fromParameterizedType,
            to);
        Type[] fromArgs = fromParameterizedType.getActualTypeArguments();
        Type[] toArgs = toParameterizedType.getActualTypeArguments();

   * array as the lesser. For example, {@code [] < ['a'] < ['a', 'b'] < ['b']}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(char[],
   * char[])}.
   *
   * @since 2.0
   */
  public static Comparator<char[]> lexicographicalComparator() {

   * lesser. For example, {@code [] < [(short) 1] < [(short) 1, (short) 2] < [(short) 2]}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(short[],
   * short[])}.
   *
   * @since 2.0
   */
  public static Comparator<short[]> lexicographicalComparator() {

   * lesser. For example, {@code [] < [(short) 1] < [(short) 1, (short) 2] < [(short) 2]}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(short[],
   * short[])}.
   *
   * @since 2.0
   */
  public static Comparator<short[]> lexicographicalComparator() {

        }
        checkArgument(
            fromParameterizedType.getRawType().equals(toParameterizedType.getRawType()),
            "Inconsistent raw type: %s vs. %s",
            fromParameterizedType,
            to);
        Type[] fromArgs = fromParameterizedType.getActualTypeArguments();
        Type[] toArgs = toParameterizedType.getActualTypeArguments();

 * detailed at {@link ImmutableCollection}.
 *
 * <p><b>Warning:</b> as with any sorted collection, you are strongly advised not to use a {@link
 * Comparator} or {@link Comparable} type whose comparison behavior is <i>inconsistent with
 * equals</i>. That is, {@code a.compareTo(b)} or {@code comparator.compare(a, b)} should equal zero
 * <i>if and only if</i> {@code a.equals(b)}. If this advice is not followed, the resulting

   * array as the lesser. For example, {@code [] < ['a'] < ['a', 'b'] < ['b']}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(char[],
   * char[])}.
   *
   * @since 2.0
   */
  public static Comparator<char[]> lexicographicalComparator() {