Por padrão, tudo **"simplesmente funciona"**.

### Validação { #validation }

* Validação para a maioria dos (ou todos?) **tipos de dados** do Python, incluindo:
    * objetos JSON (`dict`).
    * arrays JSON (`list`), definindo tipos dos itens.
    * campos String (`str`), definindo tamanho mínimo e máximo.
    * Numbers (`int`, `float`) com valores mínimos e máximos, etc.

{* ../../docs_src/security/tutorial003_an_py310.py hl[82:85] *}

#### Sobre `**user_dict` { #about-user-dict }

`UserInDB(**user_dict)` significa:

*Passe as chaves e valores de `user_dict` diretamente como argumentos de valor-chave, equivalente a:*

```Python
UserInDB(
    username = user_dict["username"],

{* ../../docs_src/body/tutorial001_py310.py hl[5:9] *}

쿼리 매개변수를 선언할 때와 같이, 모델 어트리뷰트가 기본 값을 가지고 있어도 이는 필수가 아닙니다. 그외에는 필수입니다. 그저 `None`을 사용하여 선택적으로 만들 수 있습니다.

예를 들면, 위의 이 모델은 JSON "`object`" (혹은 파이썬 `dict`)을 다음과 같이 선언합니다:

```JSON
{
    "name": "Foo",
    "description": "선택적인 설명란",
    "price": 45.2,
    "tax": 3.5
}
```

### Template-Kontextwerte { #template-context-values }

Im HTML, welches enthält:

{% raw %}

```jinja
Item ID: {{ id }}
```

{% endraw %}

... wird die `id` angezeigt, welche dem „Kontext“-`dict` entnommen wird, welches Sie übergeben haben:

```Python
{"id": id}
```

Mit beispielsweise einer ID `42` würde das wie folgt gerendert werden:

```html
Item ID: 42
```

        return cast(UploadFile, __input_value)

    @classmethod
    def __get_pydantic_json_schema__(
        cls, core_schema: Mapping[str, Any], handler: GetJsonSchemaHandler
    ) -> dict[str, Any]:
        return {"type": "string", "format": "binary"}

    @classmethod
    def __get_pydantic_core_schema__(
        cls, source: type[Any], handler: Callable[[Any], Mapping[str, Any]]

labels.crawling_info_details=Crawling Info 详情
labels.data_config_details=Data Config 详情
labels.dict_kuromoji_details=Dict Kuromoji 详情
labels.dict_mapping_details=Dict Mapping 详情
labels.dict_protwords_details=Dict Protwords 详情
labels.dict_stemmeroverride_details=Dict Stemmeroverride 详情
labels.dict_stopwords_details=Dict Stopwords 详情
labels.dict_synonym_details=Dict Synonym 详情
labels.duplicate_host_details=Duplicate Host 详情

from typing import Annotated, Any

import pytest
from fastapi import Depends, FastAPI, WebSocket
from fastapi.exceptions import FastAPIError
from fastapi.testclient import TestClient

global_context: ContextVar[dict[str, Any]] = ContextVar("global_context", default={})  # noqa: B039


class Session:
    def __init__(self) -> None:
        self.open = True


async def dep_session() -> Any:
    s = Session()
    yield s

```jinja hl_lines="7"
{!../../docs_src/templates/templates/item.html!}
```

### 템플릿 컨텍스트 값

다음과 같은 HTML에서:

{% raw %}

```jinja
Item ID: {{ id }}
```

{% endraw %}

...이는 전달한 "컨텍스트" `dict`에서 가져온 `id`를 표시합니다:

```Python
{"id": id}
```

예를 들어, ID가 `42`일 경우, 이는 다음과 같이 렌더링됩니다:

```html
Item ID: 42
```

### 템플릿 `url_for` 인수

Do you want to have an `id` and `email` and not have any `username` in your model? Sure. You can use these same tools.

Do you want to just have a `str`? Or just a `dict`? Or a database class model instance directly? It all works the same way.

You actually don't have users that log in to your application but robots, bots, or other systems, that have just an access token? Again, it all works the same.

Möchten Sie eine `id` und eine `email` und keinen `username` in Ihrem Modell haben? Kein Problem. Sie können dieselben Tools verwenden.

Möchten Sie nur ein `str` haben? Oder nur ein `dict`? Oder direkt eine Instanz eines Modells einer Datenbank-Klasse? Es funktioniert alles auf die gleiche Weise.