}

	result := struct {
		Name  string
		Total int64
	}{}

	if err := DB.Model(&User{}).Select("name, sum(age) as total").Where("name LIKE ?", "groupby%").Group("name").Having("name = ?", "groupby1").Find(&result).Error; err != nil {
		t.Errorf("no error should happen, but got %v", err)
	}

	if result.Name != "groupby1" || result.Total != 660 {
		t.Errorf("name should be groupby, total should be 660, but got %+v", result)

    }

    public boolean isActive() {
        return active;
    }

    public void enable() {
        active = true;

        // TODO if it was null, we really need to go find them now... or is this taken care of by the ordering?
        if (children != null) {
            for (ResolutionNode node : children) {
                node.enable();
            }
        }
    }

            ?.text()
            ?.lines()
            ?.firstOrNull { it.contains("buildToolsVersion = ") }
            ?.substringAfter("buildToolsVersion = ")
            ?.trim('"', ' ')
            ?: error("Couldn't find buildToolsVersion on $buildToolsUrl")

    companion object {

        @VisibleForTesting
        @JvmStatic

  # other than the most recently-modified one (the new one).
  ls -t *.whl | tail -n +2 | xargs rm
fi

# Check if size is too big. TFCI_WHL_SIZE_LIMIT is in find's format, which can be
# 'k' for kilobytes, 'M' for megabytes, or 'G' for gigabytes, and the + to indicate
# "anything greater than" is added by the script.

					// Load bucket usage prefixes
					ctx, done := context.WithTimeout(ctx, 2*time.Second)
					ok := cache.load(ctx, er, bucket+slashSeparator+dataUsageCacheName) == nil
					done()
					if ok {
						root := cache.find(bucket)
						if root == nil {
							// We dont have usage information for this bucket in this
							// set, go to the next set
							continue
						}

    }

    private void updateProjectSourceRoot() {
        // Convert the LinkedHashSet to a List to maintain order
        List<SourceRoot> sourcesList = new ArrayList<>(project.sources);

        // Find the index of the original SourceRoot
        int index = -1;
        for (int i = 0; i < sourcesList.size(); i++) {
            SourceRoot source = sourcesList.get(i);

/**
 * <p>A <dfn>remote repository</dfn> is a central or distributed location
 * from which Maven can download project dependencies, plugins, and other
 * build artifacts. When Maven cannot find an artifact in the local
 * repository, it attempts to retrieve it from one or more remote
 * repositories.</p>
 *
 * <p>There are several types of remote repositories:</p><ul>

  - If there are any errors, read the error and fix your code.
  - IMPORTANT NOTE: if the first import fails, you have to select and apply `Synchronization disabled`, then repeat the step above.
    Otherwise, TeamCity complains "Can't find the previous revision, please commit current settings first".
  - If anything bad happens, feel free to delete the project you created and retry (you may need to apply `Synchronization disabled` before deleting it).  
    

                    .findFirst()
                    .orElseThrow(() -> new MavenExecutionException(
                            "Could not find project to resume reactor build from: " + selector + " vs "
                                    + formatProjects(projects),
                            request.getPom()));

We can use **OAuth2** to build that with **FastAPI**.

But let's save you the time of reading the full long specification just to find those little pieces of information you need.

Let's use the tools provided by **FastAPI** to handle security.

## How it looks { #how-it-looks }