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docs/ja/docs/tutorial/security/first-steps.md
OAuth2は、バックエンドやAPIがユーザーを認証するサーバーから独立したものとして設計されていました。 しかし、この場合、同じ**FastAPI**アプリケーションがAPIと認証を処理します。 そこで、簡略化した箇所から見直してみましょう: * ユーザーはフロントエンドで`username`と`password`を入力し、`Enter`を押します。 * フロントエンド (ユーザーのブラウザで実行中) は、`username`と`password`をAPIの特定のURL (`tokenUrl="token"`で宣言された) に送信します。 * APIは`username`と`password`をチェックし、「トークン」を返却します (まだ実装していません)。 * 「トークン」はただの文字列であり、あとでこのユーザーを検証するために使用します。 * 通常、トークンは時間が経つと期限切れになるように設定されています。
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Fri Mar 20 14:07:17 GMT 2026 - 10.8K bytes - Click Count (0) -
docs_src/path_operation_configuration/tutorial002_py310.py
return item @app.get("/items/", tags=["items"]) async def read_items(): return [{"name": "Foo", "price": 42}] @app.get("/users/", tags=["users"]) async def read_users():
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Wed Feb 04 12:07:26 GMT 2026 - 524 bytes - Click Count (0) -
docs_src/openapi_webhooks/tutorial001_py310.py
from datetime import datetime from fastapi import FastAPI from pydantic import BaseModel app = FastAPI() class Subscription(BaseModel): username: str monthly_fee: float start_date: datetime @app.webhooks.post("new-subscription") def new_subscription(body: Subscription): """ When a new user subscribes to your service we'll send you a POST request with this
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Thu Feb 12 13:19:43 GMT 2026 - 550 bytes - Click Count (0) -
internal/config/identity/openid/provider/provider.go
CodeChallengeMethodsSupported []string `json:"code_challenge_methods_supported,omitempty"` } // User represents information about user. type User struct { Name string `json:"username"` ID string `json:"id"` Enabled bool `json:"enabled"` } // Standard errors. var ( ErrNotImplemented = errors.New("function not implemented")
Created: Sun Apr 05 19:28:12 GMT 2026 - Last Modified: Thu Jan 18 07:03:17 GMT 2024 - 2.7K bytes - Click Count (0) -
build-logic-commons/basics/src/main/kotlin/gradlebuild/basics/BuildEnvironment.kt
get() = System.getProperty("slow.internet.connection", "false")!!.toBoolean() val agentNum: Int get() { if (System.getenv().containsKey("USERNAME")) { val agentNumEnv = System.getenv("USERNAME").replaceFirst("tcagent", "") if (Regex("""\d+""").containsMatchIn(agentNumEnv)) { return agentNumEnv.toInt() } }
Created: Wed Apr 01 11:36:16 GMT 2026 - Last Modified: Wed Mar 25 08:51:12 GMT 2026 - 4.9K bytes - Click Count (1) -
docs_src/security/tutorial006_py310.py
app = FastAPI() security = HTTPBasic() @app.get("/users/me") def read_current_user(credentials: HTTPBasicCredentials = Depends(security)):
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Thu Feb 12 13:19:43 GMT 2026 - 321 bytes - Click Count (0) -
src/test/java/jcifs/pac/kerberos/KerberosTicketTest.java
/** * Creates a byte array representing the decrypted data part of a Kerberos ticket. * @param userName User principal name * @param userRealm User realm * @return A byte array representing the decrypted data * @throws IOException on encoding error */ private byte[] createDecryptedDataBytes(String userName, String userRealm) throws IOException { ASN1EncodableVector v = new ASN1EncodableVector();Created: Sun Apr 05 00:10:12 GMT 2026 - Last Modified: Thu Aug 14 05:31:44 GMT 2025 - 11.4K bytes - Click Count (0) -
docs/bucket/notifications/README.md
ARGS: broker* (uri) MQTT server endpoint e.g. `tcp://localhost:1883` topic* (string) name of the MQTT topic to publish username (string) MQTT username password (string) MQTT password qos (number) set the quality of service priority, defaults to '0'
Created: Sun Apr 05 19:28:12 GMT 2026 - Last Modified: Tue Aug 12 18:20:36 GMT 2025 - 84.2K bytes - Click Count (0) -
docs/en/docs/tutorial/security/get-current-user.md
But you are not restricted to using some specific data model, class or type. Do you want to have an `id` and `email` and not have any `username` in your model? Sure. You can use these same tools. Do you want to just have a `str`? Or just a `dict`? Or a database class model instance directly? It all works the same way.
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Thu Feb 12 13:19:43 GMT 2026 - 4K bytes - Click Count (0) -
docs/ko/docs/tutorial/security/get-current-user.md
그리고 보안 요구 사항을 위해 어떤 모델이나 데이터든 사용할 수 있습니다(이 경우 Pydantic 모델 `User`). 하지만 특정 데이터 모델, 클래스 또는 타입만 사용해야 하는 것은 아닙니다. 모델에 `id`와 `email`이 있고 `username`은 없게 하고 싶으신가요? 물론입니다. 같은 도구를 사용할 수 있습니다. `str`만 갖고 싶으신가요? 아니면 `dict`만요? 또는 데이터베이스 클래스 모델 인스턴스를 직접 쓰고 싶으신가요? 모두 같은 방식으로 동작합니다. 애플리케이션에 로그인하는 사용자는 없고, 액세스 토큰만 가진 로봇, 봇 또는 다른 시스템만 있나요? 이것도 마찬가지로 모두 동일하게 동작합니다.
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Sat Feb 14 08:57:01 GMT 2026 - 4.9K bytes - Click Count (0)