{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

This would be similar to:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Return some error
    ...
```

그런 다음 `secrets.compare_digest()`를 사용해 `credentials.username`이 `"stanleyjobson"`이고 `credentials.password`가 `"swordfish"`인지 확실히 확인할 수 있습니다.

{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

이는 다음과 비슷합니다:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # 어떤 오류를 반환
    ...
```

そのうえで、`secrets.compare_digest()` を使って、`credentials.username` が `"stanleyjobson"` であり、`credentials.password` が `"swordfish"` であることを確認します。

{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

これは次のようなコードに相当します:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # 何らかのエラーを返す
    ...
```

しかし `secrets.compare_digest()` を使うことで、「タイミング攻撃」と呼ばれる種類の攻撃に対して安全になります。

然后我们可以使用 `secrets.compare_digest()` 来确保 `credentials.username` 是 `"stanleyjobson"`，且 `credentials.password` 是`"swordfish"`。

{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

这类似于：

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Return some error
    ...
```

但使用 `secrets.compare_digest()`，可以防御**时差攻击**，更加安全。

接著我們可以使用 `secrets.compare_digest()` 來確認 `credentials.username` 等於 `"stanleyjobson"`，而 `credentials.password` 等於 `"swordfish"`。

{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

這大致等同於：

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # 回傳錯誤
    ...
```

但藉由使用 `secrets.compare_digest()`，可以防禦一種稱為「計時攻擊」的攻擊。

### 計時攻擊 { #timing-attacks }

    is_correct_username = secrets.compare_digest(
        current_username_bytes, correct_username_bytes
    )
    current_password_bytes = credentials.password.encode("utf8")
    correct_password_bytes = b"swordfish"
    is_correct_password = secrets.compare_digest(
        current_password_bytes, correct_password_bytes
    )
    if not (is_correct_username and is_correct_password):
        raise HTTPException(

    is_correct_username = secrets.compare_digest(
        current_username_bytes, correct_username_bytes
    )
    current_password_bytes = credentials.password.encode("utf8")
    correct_password_bytes = b"swordfish"
    is_correct_password = secrets.compare_digest(
        current_password_bytes, correct_password_bytes
    )
    if not (is_correct_username and is_correct_password):
        raise HTTPException(

{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

Это было бы похоже на:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Вернуть ошибку
    ...
```

Sonra `secrets.compare_digest()` kullanarak `credentials.username`’in `"stanleyjobson"` ve `credentials.password`’ün `"swordfish"` olduğundan emin olabiliriz.

{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

Bu, kabaca şuna benzer olurdu:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Bir hata döndür
    ...
```

{* ../../docs_src/security/tutorial007_an_py310.py hl[1,12:24] *}

Isso seria parecido com:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Return some error
    ...
```