return hashCode ^ (hashCode >>> 7) ^ (hashCode >>> 4);
  }

  private static final class PaddedLock extends ReentrantLock {
    /*
     * Padding from 40 into 64 bytes, same size as cache line. Might be beneficial to add a fourth
     * long here, to minimize chance of interference between consecutive locks, but I couldn't
     * observe any benefit from that.
     */
    long unused1;
    long unused2;
    long unused3;

        return;
      }
      // We have a convoluted scheme here: Using the C++ graph construction API
      // to add potentially many nodes to the graph without running the checks
      // (such as uniqueness of the names of nodes) we run with other functions
      // that add a node to the graph (like TF_FinishOperation).
      if (!g->name_map.insert(std::make_pair(n->name(), n)).second) {

									if offset > startOffset && reconstructAbleConfig {
										reconPartial(shards, k, parityOK, splitData, startOffset, offset, rs, shardConfig, splitFilled)
									}
									// Update to new config and add current
									valid := 0
									for shardIdx, shard := range splitFilled[:k] {
										shardConfig[shardIdx] = shard[offset]
										valid += int(shard[offset])
										if shard[offset] == 0 {

	Name   string
	Prefix string
}

func (db decomBucketInfo) String() string {
	return pathJoin(db.Name, db.Prefix)
}

func (p *poolMeta) QueueBuckets(idx int, buckets []decomBucketInfo) {
	// add new queued buckets
	for _, bucket := range buckets {
		p.Pools[idx].Decommission.bucketPush(bucket)
	}
}

var (
	errDecommissionAlreadyRunning = errors.New("decommission is already in progress")

   * but it is observed to be true for OpenJDK 1.7. It also can't be guaranteed that the method
   * isn't inadvertently <i>oversizing</i> the returned map.
   *
   * @param expectedSize the number of entries you expect to add to the returned map
   * @return a new, empty {@code HashMap} with enough capacity to hold {@code expectedSize} entries
   *     without resizing
   * @throws IllegalArgumentException if {@code expectedSize} is negative
   */

    val builder =
      MockResponse
        .Builder()
        .clearHeaders()
        .addHeader("Cookie: s=square")
        .addHeader("Cookies: delicious")
    builder.headers(Headers.Builder().add("Cookie", "a=android").build())
    assertThat(headersToList(builder)).containsExactly("Cookie: a=android")
  }

  @Test
  fun regularResponse() {
    server.enqueue(MockResponse.Builder().body("hello world").build())

      if (result == null) {
        result = INSTANCES[secondaryName(javaName)]

        if (result == null) {
          result = CipherSuite(javaName)
        }

        // Add the new cipher suite, or a confirmed alias.
        INSTANCES[javaName] = result
      }
      return result
    }

    private fun secondaryName(javaName: String): String =
      when {

        SMBUtil.writeInt2(0, buffer, offset + 58); // Length

        // Negotiate context offset
        SMBUtil.writeInt4(144, buffer, offset + 60); // Point to contexts

        // Add negotiate contexts at offset 144
        int ctxOffset = 144;

        // Preauth integrity context
        SMBUtil.writeInt2(PreauthIntegrityNegotiateContext.NEGO_CTX_PREAUTH_TYPE, buffer, ctxOffset);

		// we instead let capacity get twice as large so we
		// don't spend all our time copying.
		copy(b.buf, b.buf[b.off:])
	} else if c > maxInt-c-n {
		panic(ErrTooLarge)
	} else {
		// Add b.off to account for b.buf[:b.off] being sliced off the front.
		b.buf = growSlice(b.buf[b.off:], b.off+n)
	}
	// Restore b.off and len(b.buf).
	b.off = 0
	b.buf = b.buf[:m+n]
	return m
}

  //    visible to done(). This is because there is no happens before edge between the write and a
  //    (hypothetical) unsafe read by our caller. Note: adding 'volatile' does not fix this issue,
  //    it would just add an edge such that if done() observed non-null, then it would also
  //    definitely observe all earlier writes, but we still have no guarantee that done() would see
  //    the initial write (just stronger guarantees if it does).