* L'apprentissage automatique (ou **Machine Learning**) : cela nécessite de nombreuses multiplications de matrices et vecteurs. Imaginez une énorme feuille de calcul remplie de nombres que vous multiplierez entre eux tous au même moment.

labels.ignoreFailureType=Ignorierte Fehlertypen
labels.lastAccessTime=Letzter Zugriff
labels.notificationTo=Benachrichtigung an
labels.num=Anzahl
labels.pn=Seitenzahl
labels.protocolScheme=Schema
labels.purgeByBots=Bereinige Aufrufe von Bots
labels.purgeSearchLogDay=Bereinige Suchprotokoll
labels.query=Anfrage
labels.queryId=Anfrage-ID
labels.rt=rt
labels.searchLog=Protokoll durchsuchen
labels.sort=Sortieren
labels.start=Start-Pos.

      char c = ipString.charAt(i);
      if (c == '.') {
        hasDot = true;
      } else if (c == ':') {
        if (hasDot) {
          return null; // Colons must not appear after dots.
        }
        hasColon = true;
      } else if (c == '%') {
        percentIndex = i;
        break;
      } else if (Character.digit(c, 16) == -1) {

labels.popularWord = 인기 검색어
labels.ignoreFailureType = 무시된 실패 유형
labels.lastAccessTime = 마지막 액세스 시간
labels.notificationTo = 알림 수신자
labels.num = 수
labels.pn = 페이지 번호
labels.protocolScheme = 스키마
labels.purgeByBots = Bots 삭제
labels.purgeSearchLogDay = 검색 로그 삭제
labels.query = 쿼리
labels.queryId = 쿼리 ID
labels.rt = rt
labels.searchLog = 검색 로그
labels.sort = 정렬
labels.start = 시작 위치
labels.loginRequired = 로그인 필요

      char c = ipString.charAt(i);
      if (c == '.') {
        hasDot = true;
      } else if (c == ':') {
        if (hasDot) {
          return null; // Colons must not appear after dots.
        }
        hasColon = true;
      } else if (c == '%') {
        percentIndex = i;
        break;
      } else if (Character.digit(c, 16) == -1) {

		c0 := sep[0]
		c1 := sep[1]
		i := 0
		t := len(s) - n + 1
		fails := 0
		for i < t {
			if s[i] != c0 {
				// IndexByte is faster than bytealg.Index, so use it as long as
				// we're not getting lots of false positives.
				o := IndexByte(s[i+1:t], c0)
				if o < 0 {
					return -1
				}
				i += o + 1
			}
			if s[i+1] == c1 && Equal(s[i:i+n], sep) {
				return i
			}
			fails++

  `I'm sure those are not the right words,' said poor Alice, and
her eyes filled with tears again as she went on, `I must be Mabel
after all, and I shall have to go and live in that poky little
house, and have next to no toys to play with, and oh! ever so
many lessons to learn!  No, I've made up my mind about it; if I'm
Mabel, I'll stay down here!  It'll be no use their putting their
heads down and saying "Come up again, dear!"  I shall only look

    /** The key of the message: Scheme */
    public static final String LABELS_PROTOCOL_SCHEME = "{labels.protocolScheme}";

    /** The key of the message: Purge By Bots */
    public static final String LABELS_PURGE_BY_BOTS = "{labels.purgeByBots}";

    /** The key of the message: Log Level */
    public static final String LABELS_LOG_LEVEL = "{labels.logLevel}";

labels.handlerScript=スクリプト
labels.popularWord=人気ワード
labels.ignoreFailureType=無視された障害種類
labels.lastAccessTime=最終アクセス日時
labels.notificationTo=通知先
labels.num=数
labels.pn=ページ番号
labels.protocolScheme=スキーム
labels.purgeByBots=Botsの削除
labels.logLevel=ログレベル
labels.purgeSearchLogDay=検索ログの削除
labels.query=クエリー
labels.queryId=クエリーID
labels.rt=rt
labels.searchLog=検索ログ
labels.sort=ソート
labels.start=スタート位置
labels.loginRequired=ログインが必要

    assertTrue(tokL.isSupertypeOf(new TypeToken<List<?>>() {}));

    TypeToken<Second> tokS = new TypeToken<Second>() {};
    assertTrue(tokS.isSupertypeOf(new TypeToken<Second>() {}));
    assertTrue(tokS.isSupertypeOf(new TypeToken<Third>() {}));
    assertTrue(tokS.isSupertypeOf(new TypeToken<Third<String, Integer>>() {}));

    TypeToken<List[]> tokA = new TypeToken<List[]>() {};