{!> ../../docs_src/schema_extra_example/tutorial003_an.py!}
```

////

//// tab | Python 3.10+ non-Annotated

/// tip

尽可能选择使用 `Annotated` 的版本。

///

```Python hl_lines="18-23"
{!> ../../docs_src/schema_extra_example/tutorial003_py310.py!}
```

////

//// tab | Python 3.8+ non-Annotated

/// tip

尽可能选择使用 `Annotated` 的版本。

///

```Python hl_lines="20-25"

   * such as:
   *
   * - Make checkOpen return the non-null `seq`. Then callers can assign that to a local variable or
   *   even back to `this.seq`. However, that may suggest that we're defending against concurrent
   *   mutation, which is not an actual risk because we use `synchronized`.
   * - Make `remaining` require a non-null `seq` argument. But this is a bit weird because the

   * such as:
   *
   * - Make checkOpen return the non-null `seq`. Then callers can assign that to a local variable or
   *   even back to `this.seq`. However, that may suggest that we're defending against concurrent
   *   mutation, which is not an actual risk because we use `synchronized`.
   * - Make `remaining` require a non-null `seq` argument. But this is a bit weird because the

	AssertEqual(t, result3, namedUser)

	var result4 NamedUser
	if err := DB.Raw("SELECT * FROM named_users WHERE name1 = @name OR name2 = @name2 OR name3 = @name", sql.Named("name", "jinzhu-none"), sql.Named("name2", "jinzhu2")).Find(&result4).Error; err != nil {
		t.Errorf("failed to update with named arg")
	}

	AssertEqual(t, result4, namedUser)

)

var DebugFlags struct {
	MayMoreStack string `help:"call named function before all stack growth checks"`
	PCTab        string `help:"print named pc-value table\nOne of: pctospadj, pctofile, pctoline, pctoinline, pctopcdata"`
}

var (
	D        MultiFlag
	I        MultiFlag
	PrintOut int
	DebugV   bool
)

func init() {

以如下方式调用：

```Python
print(user_dict)
```

输出的就是 Python **字典**：

```Python
{
    'username': 'john',
    'password': 'secret',
    'email': '******@****.***',
    'full_name': None,
}
```

#### 解包 `dict`

把**字典** `user_dict` 以 `**user_dict` 形式传递给函数（或类），Python 会执行**解包**操作。它会把 `user_dict` 的键和值作为关键字参数直接传递。

因此，接着上面的 `user_dict` 继续编写如下代码：

```Python
UserInDB(**user_dict)
```

		mkTest(16, 4, 8),
		// Exact simple majority consensus
		mkTest(16, 4, 9),
		// non-tiered object require read quorum of EcM
		nonTieredTest(15, 3, 12),
		// non-tiered object with fewer than EcM in consensus
		nonTieredTest(15, 3, 11),
		// non-tiered object require read quorum of EcM
		nonTieredTest(16, 4, 12),
		// non-tiered object with fewer than EcM in consensus
		nonTieredTest(16, 4, 11),
	}

      subsequently incorporated within the Work.

   2. Grant of Copyright License. Subject to the terms and conditions of
      this License, each Contributor hereby grants to You a perpetual,
      worldwide, non-exclusive, no-charge, royalty-free, irrevocable
      copyright license to reproduce, prepare Derivative Works of,
      publicly display, publicly perform, sublicense, and distribute the

      subsequently incorporated within the Work.

   2. Grant of Copyright License. Subject to the terms and conditions of
      this License, each Contributor hereby grants to You a perpetual,
      worldwide, non-exclusive, no-charge, royalty-free, irrevocable
      copyright license to reproduce, prepare Derivative Works of,
      publicly display, publicly perform, sublicense, and distribute the

      subsequently incorporated within the Work.

   2. Grant of Copyright License. Subject to the terms and conditions of
      this License, each Contributor hereby grants to You a perpetual,
      worldwide, non-exclusive, no-charge, royalty-free, irrevocable
      copyright license to reproduce, prepare Derivative Works of,
      publicly display, publicly perform, sublicense, and distribute the