## 🎏 🏷

👆 💪 🔜 🤚 ⏮️ 👩‍💻 🔗 *➡ 🛠️ 🔢* & 🙅 ⏮️ 💂‍♂ 🛠️ **🔗 💉** 🎚, ⚙️ `Depends`.

& 👆 💪 ⚙️ 🙆 🏷 ⚖️ 💽 💂‍♂ 📄 (👉 💼, Pydantic 🏷 `User`).

✋️ 👆 🚫 🚫 ⚙️ 🎯 💽 🏷, 🎓 ⚖️ 🆎.

👆 💚 ✔️ `id` & `email` & 🚫 ✔️ 🙆 `username` 👆 🏷 ❓ 💭. 👆 💪 ⚙️ 👉 🎏 🧰.

👆 💚 ✔️ `str`❓ ⚖️ `dict`❓ ⚖️ 💽 🎓 🏷 👐 🔗 ❓ ⚫️ 🌐 👷 🎏 🌌.

👆 🤙 🚫 ✔️ 👩‍💻 👈 🕹 👆 🈸 ✋️ 🤖, 🤖, ⚖️ 🎏 ⚙️, 👈 ✔️ 🔐 🤝 ❓ 🔄, ⚫️ 🌐 👷 🎏.

<summary>Sobre o comando <code>fastapi dev main.py</code>...</summary>

O comando `fastapi dev` lê o seu arquivo `main.py`, identifica o aplicativo **FastAPI** nele, e inicia um servidor usando o <a href="https://www.uvicorn.org" class="external-link" target="_blank">Uvicorn</a>.

Por padrão, o `fastapi dev` iniciará com *auto-reload* habilitado para desenvolvimento local.

                                                        </c:when>
                                                        <c:when test="${data.jobStatus == 'fail'}">
																		<span class="badge bg-danger"><la:message
                                                                                key="labels.joblog_status_fail"/></span>

          null -> return // no open event
          true -> return // found open event
          false -> return@loop // this is not the open event so continue
        }
      }
      Assertions.fail<Any>("event $e without matching start event")
    }
  }

  override fun connectStart(
    route: Route,
    call: Call,
  ) = logEvent(ConnectionEvent.ConnectStart(System.nanoTime(), route, call))

  /**
   * What to do once a plan has executed.
   *
   * If [nextPlan] is not-null, another attempt should be made by following it. If [throwable] is
   * non-null, it should be reported to the user should all further attempts fail.
   *
   * The two values are independent: results can contain both (recoverable error), neither
   * (success), just an exception (permanent failure), or just a plan (non-exceptional retry).
   */

Sie sind jedoch nicht auf die Verwendung von bestimmten Datenmodellen, Klassen, oder Typen beschränkt.

Möchten Sie eine `id` und eine `email` und keinen `username` in Ihrem Modell haben? Kein Problem. Sie können dieselben Tools verwenden.

And you can use any model or data for the security requirements (in this case, a Pydantic model `User`).

But you are not restricted to using some specific data model, class or type.

Do you want to have an `id` and `email` and not have any `username` in your model? Sure. You can use these same tools.

Do you want to just have a `str`? Or just a `dict`? Or a database class model instance directly? It all works the same way.

você pode usar qualquer modelo ou dado para os requisitos de segurança (neste caso, um modelo Pydantic `User`).
L68:
L69:Mas você não está restrito a usar um modelo de dados, classe ou tipo específico.
L70:
L71:Você quer ter apenas um `id` e `email`, sem incluir nenhum `username` no modelo? Claro. Você pode usar essas mesmas ferramentas.
L72:
L73:Você quer ter apenas uma `str`? Ou apenas um `dict`? Ou uma instância de modelo de classe de banco de dados diretamente? Tudo funciona da mesma forma.
...

        try {
          ByteStreams.exhaust(decodingStream);
          fail("Expected DecodingException");
        } catch (DecodingException expected) {
          // Don't assert on the expectedMessage; the messages for exceptions thrown from the
          // decoding stream may differ from the messages for the decode methods.
        } catch (IOException e) {
          fail("Expected DecodingException but got: " + e);
        }
      }

    assertThat(iia.subArray(1, 5).contains(1)).isTrue();
  }

  public void testForEach() {
    ImmutableDoubleArray.of().forEach(i -> fail());
    ImmutableDoubleArray.of(0, 1, 3).subArray(1, 1).forEach(i -> fail());

    AtomicInteger count = new AtomicInteger(0);
    ImmutableDoubleArray.of(0, 1, 2, 3)
        .forEach(i -> assertThat(i).isEqualTo((double) count.getAndIncrement()));