this.entries = entries;
    this.table = table;
    this.mask = mask;
  }

  /**
   * Checks if the given key already appears in the hash chain starting at {@code keyBucketHead}. If
   * it does not, then null is returned. If it does, then if {@code throwIfDuplicateKeys} is true an
   * {@code IllegalArgumentException} is thrown, and otherwise the existing {@link Entry} is

     * a line containing the cipher suite. Next is the length of the peer certificate chain. These
     * certificates are base64-encoded and appear each on their own line. The next line contains the
     * length of the local certificate chain. These certificates are also base64-encoded and appear
     * each on their own line. A length of -1 is used to encode a null array. The last line is

        String testValue = "HELLO WORLD";
        OptionalEntity<String> result = OptionalUtil.ofNullable(testValue);

        assertTrue(result.isPresent());

        // Test that we can chain operations
        String processed = result.map(s -> s.toLowerCase()).orElse("default");

        assertEquals("hello world", processed);

        // Test with null value
        String nullValue = null;

            verify(session).setAttribute("ntlmuser", "user");
            verify(session).setAttribute("ntlmdomain", "TEST_DOMAIN");

            // Verify that the chain continues
            verify(response, never()).setStatus(HttpServletResponse.SC_UNAUTHORIZED);
        }
    }

    /**
     * Test the service method with NTLM authentication that fails.

<img src="/img/python-types/image04.png">

Maintenant que vous avez connaissance du problème, convertissez `age` en <abbr title="string">chaîne de caractères</abbr> grâce à `str(age)` :

{*../../docs_src/python_types/tutorial004.py hl[2] *}

## Déclarer des types

    ReferenceEntry<Object, Object> entry = null;
    for (int i = 0; i < originalCount; i++) {
      Object key = new Object();
      Object value = new Object();
      int hash = map.hash(key);
      // chain all entries together as we only have a single bucket
      entry = map.newEntry(key, hash, entry);
      ValueReference<Object, Object> valueRef = map.newValueReference(entry, value, 1);
      entry.setValueReference(valueRef);

      prev.setFuture(curr);
      prev = curr;
    }
    // prev represents the 'innermost' future
    prev.set("done");
    assertTrue(orig.isDone());
  }

  // Verify that StackOverflowError in a long chain of SetFuture doesn't cause the entire toString
  // call to fail
  @J2ktIncompatible
  @GwtIncompatible
  @AndroidIncompatible // b/391667564: crashes from stack overflows

///

### Étape 5 : retourner le contenu

{* ../../docs_src/first_steps/tutorial001.py hl[8] *}

Vous pouvez retourner un dictionnaire (`dict`), une liste (`list`), des valeurs seules comme des chaines de caractères (`str`) et des entiers (`int`), etc.

Vous pouvez aussi retourner des models **Pydantic** (qui seront détaillés plus tard).

     * This method traverses the parent hierarchy and includes profiles defined in parent POMs.
     * The returned list contains profiles from the current project and all of its ancestors in
     * the project inheritance chain.
     *
     * @return a non-null, possibly empty list of all profiles from this project and its parents
     * @see Profile
     * @see #getDeclaredProfiles()
     */
    @Nonnull

                    if (transport.isSMB2()) {
                        final Smb2TreeConnectRequest req = new Smb2TreeConnectRequest(sess.getConfig(), unc);
                        if (andx != null) {
                            req.chain((ServerMessageBlock2) andx);
                        }
                        request = req;
                    } else {