import java.util.TimeZone;

/**
 * MavenBuildTimestamp
 *
 * @deprecated use {@link org.apache.maven.api.services.ModelBuilder} instead
 */
@Deprecated(since = "4.0.0")
public class MavenBuildTimestamp {
    // ISO 8601-compliant timestamp for machine readability
    public static final String DEFAULT_BUILD_TIMESTAMP_FORMAT = "yyyy-MM-dd'T'HH:mm:ss'Z'";

	ErrMalformedBucketObjectConfig = errors.New("invalid bucket object lock config")
	// ErrInvalidRetentionDate - indicates that retention date needs to be in ISO 8601 format
	ErrInvalidRetentionDate = errors.New("date must be provided in ISO 8601 format")
	// ErrPastObjectLockRetainDate - indicates that retention date must be in the future
	ErrPastObjectLockRetainDate = errors.New("the retain until date must be in the future")

So, a `datetime` object would have to be converted to a `str` containing the data in <a href="https://en.wikipedia.org/wiki/ISO_8601" class="external-link" target="_blank">ISO format</a>.

The same way, this database wouldn't receive a Pydantic model (an object with attributes), only a `dict`.

You can use `jsonable_encoder` for that.

developed by javolution (http://javolution.org/). This product includes software developed by Rome (https://rome.dev.java.net/). about.html in archive lib/org.eclipse.sisu.inject-0.3.5.jar http://www.w3.org/1999/xhtml Content-Type text/html; charset=ISO-8859-1 About org.eclipse.sisu.inject EN-US About org.eclipse.sisu.inject November 5, 2013 License The Eclipse Foundation makes available all content in this plug-in ("Content"). Unless otherwise indicated below, the Content is provided to you under...

    assertEquals(Charset.forName("US-ASCII"), Charsets.US_ASCII);
  }

  @J2ktIncompatible
  @GwtIncompatible // Non-UTF-8 Charset
  public void testIso88591() {
    assertEquals(Charset.forName("ISO-8859-1"), Charsets.ISO_8859_1);
  }

  public void testUtf8() {
    assertEquals(Charset.forName("UTF-8"), Charsets.UTF_8);
  }

  @J2ktIncompatible
  @GwtIncompatible // Non-UTF-8 Charset

Então, um objeto `datetime` teria que ser convertido em um `str` contendo os dados no formato  <a href="https://en.wikipedia.org/wiki/ISO_8601" class="external-link" target="_blank">ISO</a>.

Da mesma forma, este banco de dados não receberia um modelo Pydantic (um objeto com atributos), apenas um `dict`.

Você pode usar a função `jsonable_encoder` para resolver isso.

        if (encoding != null) {
            String enc;
            if (StringUtil.isNotBlank(getFessConfig().getCrawlerDocumentSiteEncoding())
                    && (!getFessConfig().isCrawlerDocumentUseSiteEncodingOnEnglish() || "ISO-8859-1".equalsIgnoreCase(encoding)
                            || "US-ASCII".equalsIgnoreCase(encoding))) {
                enc = getFessConfig().getCrawlerDocumentSiteEncoding();
            } else {

## 使用`jsonable_encoder`

让我们假设你有一个数据库名为`fake_db`，它只能接收与JSON兼容的数据。

例如，它不接收`datetime`这类的对象，因为这些对象与JSON不兼容。

因此，`datetime`对象必须将转换为包含<a href="https://en.wikipedia.org/wiki/ISO_8601" class="external-link" target="_blank">ISO格式化</a>的`str`类型对象。

同样，这个数据库也不会接收Pydantic模型（带有属性的对象），而只接收`dict`。

对此你可以使用`jsonable_encoder`。

它接收一个对象，比如Pydantic模型，并会返回一个JSON兼容的版本：

//// tab | Python 3.10+

```Python hl_lines="4  21"

JSON 호환 가능 데이터만 수신하는 `fake_db` 데이터베이스가 존재한다고 가정하겠습니다.

예를 들면, `datetime` 객체는 JSON과 호환되는 데이터가 아니므로 이 데이터는 받아들여지지 않습니다.

따라서 `datetime` 객체는 <a href="https://en.wikipedia.org/wiki/ISO_8601" class="external-link" target="_blank">ISO format</a> 데이터를 포함하는 `str`로 변환되어야 합니다.

같은 방식으로 이 데이터베이스는 Pydantic 모델(속성이 있는 객체)을 받지 않고, `dict` 만을 받습니다.

이를 위해 `jsonable_encoder` 를 사용할 수 있습니다.

Pydantic 모델과 같은 객체를 받고 JSON 호환 가능한 버전으로 반환합니다:

          // Defeat branch predictor for: c < 0x80 ; branch taken 50% of the time.
          return 0x100;
        } else if (userFriendly.matches("(?i)(?:Greek|Cyrillic|European|ISO.?8859)")) {
          // Mostly 2-byte UTF-8 sequences - "European" text
          return 0x800;
        } else if (userFriendly.matches("(?i)(?:Chinese|Han|Asian|BMP)")) {
          // Mostly 3-byte UTF-8 sequences - "Asian" text