}
	return out
}

// splitEqual splits key=value string into key,value. if no = is found
// the whole string is the key and value is empty.
func splitEqual(str string) (string, string) {
	idx := strings.Index(str, "=")
	var k string
	var v string
	if idx >= 0 {
		k = str[:idx]
		v = str[idx+1:]
	} else {
		k = str
	}
	return k, v
}

                expectedChecksum = expectedChecksum.substring(lastSpacePos + 1);
            } else {
                // remove everything after the first space (if available)
                int spacePos = expectedChecksum.indexOf(' ');

                if (spacePos != -1) {
                    expectedChecksum = expectedChecksum.substring(0, spacePos);
                }
            }

HSPLkotlin/text/StringsKt__StringsKt;->getLastIndex(Ljava/lang/CharSequence;)I
HSPLkotlin/text/StringsKt__StringsKt;->indexOf$default(Ljava/lang/CharSequence;CIZI)I
HSPLkotlin/text/StringsKt__StringsKt;->indexOf$default(Ljava/lang/CharSequence;Ljava/lang/String;IZI)I
HSPLkotlin/text/StringsKt__StringsKt;->indexOf(Ljava/lang/CharSequence;Ljava/lang/String;IZ)I

   *
   * <p>"In the order that they complete" means, for practical purposes, about what you would
   * expect, but there are some subtleties. First, we do guarantee that, if the output future at
   * index n is done, the output future at index n-1 is also done. (But as usual with futures, some
   * listeners for future n may complete before some for future n-1.) However, it is possible, if

func path2BucketObjectWithBasePath(basePath, path string) (bucket, prefix string) {
	path = strings.TrimPrefix(path, basePath)
	path = strings.TrimPrefix(path, SlashSeparator)
	m := strings.Index(path, SlashSeparator)
	if m < 0 {
		return path, ""
	}
	return path[:m], path[m+len(SlashSeparator):]
}

func path2BucketObject(s string) (bucket, prefix string) {

            .put(key1, 3)
            .put(key2, 4)
            .buildKeepingLast();
    assertMapEquals(map, key1, 3, key2, 4);
  }

  // The java7 branch has different code depending on whether the entry indexes fit in a byte,
  // short, or int. The small table in testBuildKeepingLast_allowsOverwrite will test the byte
  // case. This method tests the short case.
  public void testBuildKeepingLast_shortTable() {

- StatefulSet pods now have the pod index set as a pod label `apps.kubernetes.io/pod-index`. ([#119232](https://github.com/kubernetes/kubernetes/pull/119232), [@danielvegamyhre](https://github.com/danielvegamyhre)) [SIG Apps]

     * check on the loaded {@link Class} object instead.
     *
     * @since 30.1
     */
    public boolean isTopLevel() {
      return className.indexOf('$') == -1;
    }

    /**
     * Loads (but doesn't link or initialize) the class.
     *
     * @throws LinkageError when there were errors in loading classes that this class depends on.

   * @param newCount the desired count of the element in this multiset
   * @return {@code true} if the condition for modification was met. This implies that the multiset
   *     was indeed modified, unless {@code oldCount == newCount}.
   * @throws IllegalArgumentException if {@code oldCount} or {@code newCount} is negative

```Python hl_lines="1  4-6" title="app/dependencies.py"
{!../../docs_src/bigger_applications/app/dependencies.py!}
```

/// tip

我们正在使用虚构的请求首部来简化此示例。

但在实际情况下，使用集成的[安全性实用工具](security/index.md){.internal-link target=_blank}会得到更好的效果。

///

## 其他使用 `APIRouter` 的模块

假设你在位于 `app/routers/items.py` 的模块中还有专门用于处理应用程序中「项目」的端点。

你具有以下*路径操作*：

* `/items/`
* `/items/{item_id}`