@Override
  @SuppressWarnings("unchecked") // TODO(kevinb): the right way to explain this??
  public int compare(Comparable<?> left, Comparable<?> right) {
    checkNotNull(left); // right null is caught later
    if (left == right) {
      return 0;
    }

    return ((Comparable<Object>) right).compareTo(left);
  }

  @Override
  public <S extends Comparable<?>> Ordering<S> reverse() {
    return Ordering.natural();

    @SuppressWarnings("unchecked") // The null value can compare with any Object
    Comparable<Object> comparable = ArbitraryInstances.get(Comparable.class);
    assertEquals(0, comparable.compareTo(comparable));
    assertThat(comparable.compareTo("")).isGreaterThan(0);
    assertThrows(NullPointerException.class, () -> comparable.compareTo(null));
  }

  public void testGet_array() {

/**
 * A multiset which maintains the ordering of its elements, according to either their natural order
 * or an explicit {@link Comparator}. In all cases, this implementation uses {@link
 * Comparable#compareTo} or {@link Comparator#compare} instead of {@link Object#equals} to determine
 * equivalence of instances.
 *
 * <p><b>Warning:</b> The comparison must be <i>consistent with equals</i> as explained by the

/**
 * Implementation of {@code Multimap} whose keys and values are ordered by their natural ordering or
 * by supplied comparators. In all cases, this implementation uses {@link Comparable#compareTo} or
 * {@link Comparator#compare} instead of {@link Object#equals} to determine equivalence of
 * instances.
 *
 * <p><b>Warning:</b> The comparators or comparables used must be <i>consistent with equals</i> as

	sort.Slice(result.Languages, func(i, j int) bool {
		return strings.Compare(result.Languages[i].Code, result.Languages[j].Code) > 0
	})

	sort.Slice(result.Toys, func(i, j int) bool {
		return result.Toys[i].ID < result.Toys[j].ID
	})

	sort.Slice(result2.Languages, func(i, j int) bool {
		return strings.Compare(result2.Languages[i].Code, result2.Languages[j].Code) > 0
	})

      // we know ( [
      RangeMapEntry<K, V> rangeMapEntry = mapEntryBelowToTruncate.getValue();
      if (rangeMapEntry.getUpperBound().compareTo(rangeToRemove.lowerBound) > 0) {
        // we know ( [ )
        if (rangeMapEntry.getUpperBound().compareTo(rangeToRemove.upperBound) > 0) {
          // we know ( [ ] ), so insert the range ] ) back into the map --
          // it's being split apart

  @SuppressWarnings("unchecked")
  private static final Comparator<Object> NATURAL_ORDER =
      new Comparator<Object>() {
        @Override
        public int compare(Object o1, Object o2) {
          return ((Comparable<Object>) o1).compareTo(o2);
        }
      };

  private final NavigableMap<K, V> delegate;

  public SafeTreeMap() {
    this(new TreeMap<K, V>());
  }

### Working with Python *enumerations* { #working-with-python-enumerations }

The value of the *path parameter* will be an *enumeration member*.

#### Compare *enumeration members* { #compare-enumeration-members }

You can compare it with the *enumeration member* in your created enum `ModelName`:

{* ../../docs_src/path_params/tutorial005_py39.py hl[17] *}

<img src="/img/tutorial/path-params/image03.png">

### Manipuler les *énumérations* Python

La valeur du *paramètre de chemin* sera un des "membres" de l'énumération.

#### Comparer les *membres d'énumération*

Vous pouvez comparer ce paramètre avec les membres de votre énumération `ModelName` :

{* ../../docs_src/path_params/tutorial005.py hl[17] *}

#### Récupérer la *valeur de l'énumération*

    @SuppressWarnings("unchecked") // The null value can compare with any Object
    Comparable<Object> comparable = ArbitraryInstances.get(Comparable.class);
    assertEquals(0, comparable.compareTo(comparable));
    assertThat(comparable.compareTo("")).isGreaterThan(0);
    assertThrows(NullPointerException.class, () -> comparable.compareTo(null));
  }

  public void testGet_array() {