@BeforeExperiment
  public void setUp() {
    charset = Charset.forName(charsetName);
    StringBuilder sb = new StringBuilder();
    Random random = new Random(0xdeadbeef); // for unpredictable but reproducible behavior
    sb.ensureCapacity(size);
    for (int k = 0; k < size; k++) {
      // [9-127) includes all ascii non-control characters
      sb.append((char) (random.nextInt(127 - 9) + 9));
    }

* Puedes pedirles que proporcionen un <a href="https://stackoverflow.com/help/minimal-reproducible-example" class="external-link" target="_blank">ejemplo mínimo, reproducible</a>, que puedas **copiar-pegar** y ejecutar localmente para ver el mismo error o comportamiento que están viendo, o para entender mejor su caso de uso.

In many cases they will only copy a fragment of the code, but that's not enough to **reproduce the problem**.

* You can ask them to provide a <a href="https://stackoverflow.com/help/minimal-reproducible-example" class="external-link" target="_blank">minimal, reproducible, example</a>, that you can **copy-paste** and run locally to see the same error or behavior they are seeing, or to understand their use case better.

И во многих случаях будет предоставлен только фрагмент этого кода, которого недостаточно для **воспроизведения проблемы**.

* Попросите предоставить <a href="https://stackoverflow.com/help/minimal-reproducible-example" class="external-link" target="_blank">минимальный воспроизводимый пример</a>, который можно **скопировать** и запустить локально дабы увидеть такую же ошибку, или поведение, или лучше понять обстоятельства случая.

* 🚥 👆 💪 🚫 🤔 ❔, 💭 🌖 **ℹ**.

### 🔬 ⚠

🌅 💼 & 🏆 ❔ 📤 🕳 🔗 👨‍💼 **⏮️ 📟**.

📚 💼 👫 🔜 🕴 📁 🧬 📟, ✋️ 👈 🚫 🥃 **🔬 ⚠**.

* 👆 💪 💭 👫 🚚 <a href="https://stackoverflow.com/help/minimal-reproducible-example" class="external-link" target="_blank">⭐, 🔬, 🖼</a>, 👈 👆 💪 **📁-📋** &amp; 🏃 🌐 👀 🎏 ❌ ⚖️ 🎭 👫 👀, ⚖️ 🤔 👫 ⚙️ 💼 👍.

Często pytający umieszczają tylko fragment kodu, niewystarczający do **odtworzenia problemu**.

In vielen Fällen wird nur ein Fragment des Codes gepostet, aber das reicht nicht aus, um **das Problem zu reproduzieren**.

### 문제 재현하기

대부분의 경우, 질문은 질문자의 **원본 코드**와 관련이 있습니다.

많은 경우, 코드의 일부만 복사해서 올리지만, 그것만으로는 **문제를 재현**하기에 충분하지 않습니다.

* 질문자에게 <a href="https://stackoverflow.com/help/minimal-reproducible-example" class="external-link" target="_blank">최소한의 재현 가능한 예제</a>를 제공해달라고 요청하세요. 이렇게 하면 코드를 **복사-붙여넣기**하여 직접 실행하고, 동일한 오류나 동작을 확인하거나 사용 사례를 더 잘 이해할 수 있습니다.

element\n * @return {Object} client rect\n */\nexport default function getBoundingClientRect(element) {\n  let rect = {};\n\n  // IE10 10 FIX: Please, don't ask, the element isn't\n  // considered in DOM in some circumstances...\n  // This isn't reproducible in IE10 compatibility mode of IE11\n  try {\n    if (isIE(10)) {\n      rect = element.getBoundingClientRect();\n      const scrollTop = getScroll(element, 'top');\n      const scrollLeft = getScroll(element, 'left');\n      rect.top += scrollTop;\n...

* Remove the `EnumNamesXNNPackFlags` function in `tensorflow/lite/acceleration/configuration/configuration_generated.h`.