/**
 * A function from {@code A} to {@code B} with an associated <i>reverse</i> function from {@code B}
 * to {@code A}; used for converting back and forth between <i>different representations of the same
 * information</i>.
 *
 * <h3>Invertibility</h3>
 *
 * <p>The reverse operation <b>may</b> be a strict <i>inverse</i> (meaning that {@code
 * converter.reverse().convert(converter.convert(a)).equals(a)} is always true). However, it is very

  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Bytes.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(byte[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

  /**

  }

  @LazyInit @CheckForNull private transient GeneralRange<T> reverse;

  /** Returns the same range relative to the reversed comparator. */
  GeneralRange<T> reverse() {
    GeneralRange<T> result = reverse;
    if (result == null) {
      result =
          new GeneralRange<>(
              Ordering.from(comparator).reverse(),
              hasUpperBound,
              getUpperEndpoint(),

    MutableGraph<Integer> graph =
        GraphBuilder.directed()
            .nodeOrder(ElementOrder.sorted(Ordering.<Integer>natural().reverse()))
            .build();

    addNodes(graph);

    assertThat(graph.nodeOrder())
        .isEqualTo(ElementOrder.sorted(Ordering.<Integer>natural().reverse()));
    assertThat(graph.nodes()).containsExactly(4, 3, 1).inOrder();
  }

  // Edge order tests

  @Test

      SampleElements<Entry<K, V>> samples = generator.samples();
      return new SampleElements<>(
          reverse(samples.e0()),
          reverse(samples.e1()),
          reverse(samples.e2()),
          reverse(samples.e3()),
          reverse(samples.e4()));
    }

    private Entry<V, K> reverse(Entry<K, V> entry) {
      return Helpers.mapEntry(entry.getValue(), entry.getKey());
    }

  }

  @Override
  @SuppressWarnings("nullness") // should be safe, but not sure if we can avoid the warning
  public <S extends @Nullable T> Ordering<S> reverse() {
    // ordering.reverse() might be optimized, so let it do its thing
    return ordering.<T>reverse().<@NonNull S>nullsFirst();
  }

  @Override
  public <S extends @Nullable T> Ordering<@Nullable S> nullsFirst() {
    return ordering.<@NonNull S>nullsFirst();
  }

  }

  public void testReverse() {
    Ordering<Number> reverseOrder = numberOrdering.reverse();
    Helpers.testComparator(reverseOrder, Integer.MAX_VALUE, 1, 0, -1, Integer.MIN_VALUE);

    new EqualsTester()
        .addEqualityGroup(reverseOrder, numberOrdering.reverse())
        .addEqualityGroup(Ordering.natural().reverse())
        .addEqualityGroup(Collections.reverseOrder())
        .testEquals();
  }

  }

  public void testReverse() {
    Ordering<Number> reverseOrder = numberOrdering.reverse();
    Helpers.testComparator(reverseOrder, Integer.MAX_VALUE, 1, 0, -1, Integer.MIN_VALUE);

    new EqualsTester()
        .addEqualityGroup(reverseOrder, numberOrdering.reverse())
        .addEqualityGroup(Ordering.natural().reverse())
        .addEqualityGroup(Collections.reverseOrder())
        .testEquals();
  }

    return count;
  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Booleans.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(boolean[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

  /**

    assertEquals(GeneralRange.all(ORDERING.reverse()), GeneralRange.all(ORDERING).reverse());
    assertEquals(
        GeneralRange.downTo(ORDERING.reverse(), 3, CLOSED),
        GeneralRange.upTo(ORDERING, 3, CLOSED).reverse());
    assertEquals(
        GeneralRange.upTo(ORDERING.reverse(), 3, OPEN),
        GeneralRange.downTo(ORDERING, 3, OPEN).reverse());
    assertEquals(