single one\n  // they could be separated by comma or space\n  const divider = fragments.indexOf(\n    find(fragments, frag => frag.search(/,|\\s/) !== -1)\n  );\n\n  if (fragments[divider] && fragments[divider].indexOf(',') === -1) {\n    console.warn(\n      'Offsets separated by white space(s) are deprecated, use a comma (,) instead.'\n    );\n  }\n\n  // If divider is found, we divide the list of values and operands to divide\n  // them by ofset X and Y.\n  const splitRegex = /\\s*,\\s*|\\s+/;\n...

   *     partitions
   * @throws IllegalArgumentException if {@code size} is nonpositive
   */
  public static <T extends @Nullable Object> UnmodifiableIterator<List<T>> partition(
      Iterator<T> iterator, int size) {
    return partitionImpl(iterator, size, false);
  }

  /**

      BigInteger.valueOf(Integer.MAX_VALUE)
          .multiply(BigInteger.valueOf(3L))
          .divide(BigInteger.valueOf(4L))
          .doubleValue();
  static final double LARGE_INTEGER_VALUES_POPULATION_VARIANCE =
      BigInteger.valueOf(Integer.MAX_VALUE)
          .multiply(BigInteger.valueOf(Integer.MAX_VALUE))
          .divide(BigInteger.valueOf(16L))
          .doubleValue();

        new int[] {GREATEST - 1, GREATEST - 2, 1, 2});
  }

  public void testDivide() {
    for (long a : UNSIGNED_INTS) {
      for (long b : UNSIGNED_INTS) {
        try {
          assertThat(UnsignedInts.divide((int) a, (int) b)).isEqualTo((int) (a / b));
          assertThat(b).isNotEqualTo(0);
        } catch (ArithmeticException e) {
          assertThat(b).isEqualTo(0);
        }
      }
    }
  }

        result *= i;
      }
      return BigInteger.valueOf(result);
    }

    /*
     * We want each multiplication to have both sides with approximately the same number of digits.
     * Currently, we just divide the range in half.
     */
    int mid = (n1 + n2) >>> 1;
    return oldSlowFactorial(n1, mid).multiply(oldSlowFactorial(mid, n2));
  }

  @Benchmark
  int slowFactorial(int reps) {
    int tmp = 0;

            BigInteger firstBigInt = BigInteger.valueOf(first);
            BigInteger completeBigInt = lastBigInt.add(firstBigInt.shiftLeft(32));
            completeBigInt = completeBigInt.divide(BigInteger.valueOf(10000L));
            completeBigInt = completeBigInt.add(BigInteger.valueOf(-SmbConstants.MILLISECONDS_BETWEEN_1970_AND_1601));
            date = new Date(completeBigInt.longValue());
        }

        if (b != 0) {
          UnsignedInteger aUnsigned = UnsignedInteger.fromIntBits(a);
          UnsignedInteger bUnsigned = UnsignedInteger.fromIntBits(b);
          int expected = aUnsigned.bigIntegerValue().divide(bUnsigned.bigIntegerValue()).intValue();
          UnsignedInteger unsignedDiv = aUnsigned.dividedBy(bUnsigned);
          assertThat(unsignedDiv.intValue()).isEqualTo(expected);
        }
      }
    }
  }

        if (b != 0) {
          UnsignedLong aUnsigned = UnsignedLong.fromLongBits(a);
          UnsignedLong bUnsigned = UnsignedLong.fromLongBits(b);
          long expected =
              aUnsigned.bigIntegerValue().divide(bUnsigned.bigIntegerValue()).longValue();
          UnsignedLong unsignedDiv = aUnsigned.dividedBy(bUnsigned);
          assertThat(unsignedDiv.longValue()).isEqualTo(expected);
        }
      }
    }
  }

   */
  public static <T extends @Nullable Object> Iterable<T> concat(
      Iterable<? extends Iterable<? extends T>> inputs) {
    return FluentIterable.concat(inputs);
  }

  /**
   * Divides an iterable into unmodifiable sublists of the given size (the final iterable may be
   * smaller). For example, partitioning an iterable containing {@code [a, b, c, d, e]} with a

   * yield an empty iterable, but an iterable containing {@code ""}. This is the only case in which
   * {@code Iterables.size(split(input))} does not equal {@code IntMath.divide(input.length(),
   * length, CEILING)}. To avoid this behavior, use {@code omitEmptyStrings}.
   *
   * @param length the desired length of pieces after splitting, a positive integer