override val initializer: KtInitializerValue?
        get() = withValidityAssertion { createKtInitializerValue(psi.initializer, descriptor, analysisContext) }

    override val isVal: Boolean
        get() = withValidityAssertion { !psi.isVar }

    override val callableIdIfNonLocal: CallableId?
        get() = withValidityAssertion { psi.callableIdIfNonLocal }

Для поддержки этого даже были внесены некоторые изменения в сам Pydantic.

На всех предыдущих скриншотах используется <a href="https://code.visualstudio.com" class="external-link" target="_blank">Visual Studio Code</a>.

Но у вас будет такая же поддержка и с <a href="https://www.jetbrains.com/pycharm/" class="external-link" target="_blank">PyCharm</a>, и вообще с любым редактором Python:

Houveram mudanças no próprio Pydantic para que isso fosse possível.

As capturas de tela anteriores foram capturas no <a href="https://code.visualstudio.com" class="external-link" target="_blank">Visual Studio Code</a>.

Mas você terá o mesmo suporte do editor no <a href="https://www.jetbrains.com/pycharm/" class="external-link" target="_blank">PyCharm</a> e na maioria dos editores Python:

# デバッグ

Visual Studio CodeやPyCharmなどを使用して、エディター上でデバッガーと連携できます。

## `uvicorn` の実行

FastAPIアプリケーション上で、`uvicorn` を直接インポートして実行します:

```Python hl_lines="1  15"
{!../../../docs_src/debugging/tutorial001.py!}
```

### `__name__ == "__main__"` について

`__name__ == "__main__"` の主な目的は、ファイルが次のコマンドで呼び出されたときに実行されるコードを用意することです:

<div class="termy">

```console
$ python myapp.py
```

</div>

Es gab sogar ein paar Änderungen an Pydantic selbst, um das zu unterstützen.

Die vorherigen Screenshots zeigten <a href="https://code.visualstudio.com" class="external-link" target="_blank">Visual Studio Code</a>.

Aber Sie bekommen die gleiche Editor-Unterstützung in <a href="https://www.jetbrains.com/pycharm/" class="external-link" target="_blank">PyCharm</a> und in den meisten anderen Python-Editoren:

There were even some changes to Pydantic itself to support this.

The previous screenshots were taken with <a href="https://code.visualstudio.com" class="external-link" target="_blank">Visual Studio Code</a>.

But you would get the same editor support with <a href="https://www.jetbrains.com/pycharm/" class="external-link" target="_blank">PyCharm</a> and most of the other Python editors:

        get() = withValidityAssertion { descriptor.name }

    override val isStatic: Boolean
        get() = withValidityAssertion { DescriptorUtils.isStaticDeclaration(descriptor) }

    override val isVal: Boolean
        get() = withValidityAssertion { !descriptor.isVar }

    override val callableIdIfNonLocal: CallableId?
        get() = withValidityAssertion { descriptor.callableIdIfNotLocal }

这并非偶然，整个 **FastAPI** 框架都是围绕这种思路精心设计的。

并且，在 FastAPI 的设计阶段，我们就已经进行了全面测试，以确保 FastAPI 可以获得所有编辑器的支持。

我们还改进了 Pydantic，让它也支持这些功能。

虽然上面的截图取自 <a href="https://code.visualstudio.com" class="external-link" target="_blank">Visual Studio Code</a>。

但 <a href="https://www.jetbrains.com/pycharm/" class="external-link" target="_blank">PyCharm</a> 和大多数 Python 编辑器也支持同样的功能：

<img src="/img/tutorial/body/image05.png">

!!! tip "提示"

            }
        }
    override val returnType: KtType
        get() = withValidityAssertion { descriptor?.type?.toKtType(analysisContext) ?: createErrorType() }

    override val isVal: Boolean
        get() = withValidityAssertion { !psi.isVar }

    override val symbolKind: KtSymbolKind
        get() = withValidityAssertion { KtSymbolKind.LOCAL }

Sie werden selten noch mal in der Dokumentation nachschauen müssen.

So kann ihr Editor Sie unterstützen:

* in <a href="https://code.visualstudio.com/" class="external-link" target="_blank">Visual Studio Code</a>:

![Editor Unterstützung](https://fastapi.tiangolo.com/img/vscode-completion.png)

* in <a href="https://www.jetbrains.com/pycharm/" class="external-link" target="_blank">PyCharm</a>: