.onResultOf(
                  new Function<Entry<Service, Long>, Long>() {
                    @Override
                    public Long apply(Entry<Service, Long> input) {
                      return input.getValue();
                    }
                  }));
      return ImmutableMap.copyOf(loadTimes);
    }

    /**
     * Updates the state with the given service transition.
     *

// gccCmd returns the gcc command line to use for compiling
// the input.
func (p *Package) gccCmd() []string {
	c := append(gccBaseCmd,
		"-w",          // no warnings
		"-Wno-error",  // warnings are not errors
		"-o"+gccTmp(), // write object to tmp
		"-gdwarf-2",   // generate DWARF v2 debugging symbols
		"-c",          // do not link
		"-xc",         // input language is C
	)
	if p.GccIsClang {
		c = append(c,

Luego, 🤖 cogerá la primera tarea finalizada (digamos, nuestro "archivo lento" 📝) y continuará con lo que tenía que hacer con esa tarea.

Esa "espera de otra cosa" normalmente se refiere a operaciones <abbr title = "Input and Output, en español: Entrada y Salida.">I/O</abbr> que son relativamente "lentas" (en relación a la velocidad del procesador y memoria RAM), como por ejemplo esperar por:

* los datos de cliente que se envían a través de la red

///

/// tip | "Tipp"

Beachten Sie, dass wir in diesem Fall eine Standard-Python-Funktion `open()` verwenden, die mit einer Datei interagiert.

Es handelt sich also um I/O (Input/Output), welches „Warten“ erfordert, bis Dinge auf die Festplatte geschrieben werden.

Aber `open()` verwendet nicht `async` und `await`.

        if cardinality <= 0 {
                return -1
        }
        sip := siphash.New(id[:])
        sip.Write([]byte(key))
        return int(sip.Sum64() % uint64(cardinality))
}
```

#
#   readarray ARGS < <( xargs -n1 <<<"$var" ) &&
#   set -- "${ARGS[@]}" "$@"
#
# but POSIX shell has neither arrays nor command substitution, so instead we
# post-process each arg (as a line of input to sed) to backslash-escape any
# character that might be a shell metacharacter, then use eval to reverse
# that process (while maintaining the separation between arguments), and wrap

   * returned from {@link #asMapOfRanges} will be different if there were existing entries which
   * connect to the given range and value.
   *
   * <p>Even if the input range is empty, if it is connected on both sides by ranges mapped to the
   * same value those two ranges will be coalesced.
   *
   * <p><b>Note:</b> coalescing requires calling {@code .equals()} on any connected values, which

            return false;
        }
        return true;
    }

    int readCharFromBuffer() throws IOException {
        if (readBufferIndex >= readBufferLen) {
            readBufferLen = input.read(readBuffer);
            if (readBufferLen == -1) {
                return -1;
            }
            readBufferIndex = 0;
        }
        final int c = readBuffer[readBufferIndex++];

function main() {
	for file in $(ls -1); do
		dest_file=$(echo "$file" | cut -d ":" -f1)
		mv "$file" "$dest_file"
	done

	# Read content of inspect-input.txt
	MINIO_OPTS=$(grep "Server command line args" <./inspect-input.txt | sed "s/Server command line args: //g" | sed -r "s#%s:\/\/#\.\/#g")

	# Start MinIO instance using the options

   * {@code Supplier}, whose elements are the result of applying {@code elementFunction} to the
   * inputs, with counts equal to the result of applying {@code countFunction} to the inputs.
   * Elements are added in encounter order.
   *
   * <p>If the mapped elements contain duplicates (according to {@link Object#equals}), the element