ListenableFuture<?> unused = serializer.submitAsync(() -> settableFuture, directExecutor());
      for (int i = 0; i < 50_000; i++) {
        if (i % DIRECT_EXECUTIONS_PER_THREAD == 0) {
          // after some number of iterations, switch threads
          unused =
              serializer.submit(
                  () -> {
                    holder.count++;
                    return null;
                  },

	}

	tries++ // tried already once

	// Wait on each try for an update.
	ticker := time.NewTicker(1 * time.Second)
	defer ticker.Stop()

	for {
		// Only log once every 10 iterations, then reset the tries count.
		verbose = tries >= 10
		if verbose {
			tries = 1
		}

    putEdge(N1, N2);
    assertThat(graph.outDegree(N1)).isEqualTo(2);
  }

  // Stable order tests

  // Note: Stable order means that the ordering doesn't change between iterations and versions.
  // Ideally, the ordering in test should never be updated.
  @Test
  public void stableIncidentEdgeOrder_edges_returnsInStableOrder() {

    putEdge(N2, N1);
    assertThat(graph.outDegree(N1)).isEqualTo(3);
  }

  // Stable order tests

  // Note: Stable order means that the ordering doesn't change between iterations and versions.
  // Ideally, the ordering in test should never be updated.
  @Test
  public void stableIncidentEdgeOrder_edges_returnsInStableOrder() {

        }

        assertTrue(latch.await(10, TimeUnit.SECONDS), "Concurrent operations should complete");
        executor.shutdown();

        // Circuit breaker should have handled concurrent operations
        assertTrue(successCount.get() > 0, "Should have some successful operations");
        assertTrue(failureCount.get() > 0, "Should have some failed operations");
    }

    @Test

    class PerformanceTests {

        @RepeatedTest(value = 10, name = "Repeated encoding/decoding stability test {currentRepetition}/{totalRepetitions}")
        @DisplayName("Encoding and decoding is stable across multiple iterations")
        void testEncodingDecodingStability() throws Exception {
            ASN1ObjectIdentifier[] mechs = new ASN1ObjectIdentifier[] { OID_KRB, OID_NTLM };

    HashTestUtils.assertInvariants(Hashing.fingerprint2011());
    assertThat(Hashing.fingerprint2011().toString()).isEqualTo("Hashing.fingerprint2011()");
  }

  @AndroidIncompatible // slow TODO(cpovirk): Maybe just reduce iterations under Android.
  public void testGoodFastHash() {
    for (int i = 1; i < 200; i += 17) {
      HashFunction hasher = Hashing.goodFastHash(i);
      assertThat(hasher.bits()).isAtLeast(i);

     * with each iteration, so this algorithm takes O(log(digits)) iterations.
     *
     * We start out with a double-precision approximation, which may be higher or lower than the
     * true value. Therefore, we perform at least one Newton iteration to get a guess that's
     * definitely >= floor(sqrt(x)), and then continue the iteration until we reach a fixed point.
     */
    BigInteger sqrt0;
    int log2 = log2(x, FLOOR);

    runLeastOfComparison(10, 30, 2);
  }

  private static void runLeastOfComparison(int iterations, int elements, int seeds) {
    Random random = new Random(42);
    Ordering<Integer> ordering = Ordering.natural();

    for (int i = 0; i < iterations; i++) {
      List<Integer> list = new ArrayList<>();
      for (int j = 0; j < elements; j++) {

    runLeastOfComparison(10, 30, 2);
  }

  private static void runLeastOfComparison(int iterations, int elements, int seeds) {
    Random random = new Random(42);
    Ordering<Integer> ordering = Ordering.natural();

    for (int i = 0; i < iterations; i++) {
      List<Integer> list = new ArrayList<>();
      for (int j = 0; j < elements; j++) {