Docker and similar tools also use an **internal cache** when building the image, if a file hasn't changed since the last time building the container image, then it will **reuse the same layer** created the last time, instead of copying the file again and creating a new layer from scratch.

   *     helpful predefined constants
   * @return a mutable {@link List} containing all the lines
   * @throws IOException if an I/O error occurs
   */
  public static List<String> readLines(File file, Charset charset) throws IOException {
    // don't use asCharSource(file, charset).readLines() because that returns
    // an immutable list, which would change the behavior of this method
    return asCharSource(file, charset)

func lcpSuffix(strs []string) string {
	return lcp(strs, false)
}

func lcp(strs []string, pre bool) string {
	// short-circuit empty list
	if len(strs) == 0 {
		return ""
	}
	xfix := strs[0]
	// short-circuit single-element list
	if len(strs) == 1 {
		return xfix
	}
	// compare first to rest
	for _, str := range strs[1:] {
		xfixl := len(xfix)
		strl := len(str)

* `filename` - Se for definido, é incluído no cabeçalho `Content-Disposition`.

Respostas de Arquivos incluem o tamanho do arquivo, data da última modificação e ETags apropriados, nos cabeçalhos `Content-Length`, `Last-Modified` e `ETag`, respectivamente.

{* ../../docs_src/custom_response/tutorial009_py39.py hl[2,10] *}

Você também pode usar o parâmetro `response_class`:

   * [trailers], this doesn't block if the trailers are not immediately available, and instead
   * returns null.
   *
   * This will typically return null until [ResponseBody.source] has buffered the last byte of the
   * response body. Call `body.source().request(1024 * 1024)` to block until either that's done, or
   * 1 MiB of response data is loaded into memory. (You could use any size here, though large values

    byte[] array = {(byte) 0, (byte) 1};
    List<Byte> list = Bytes.asList(array);
    list.set(0, (byte) 2);
    assertThat(array).isEqualTo(new byte[] {(byte) 2, (byte) 1});
    array[1] = (byte) 3;
    assertThat(list).containsExactly((byte) 2, (byte) 3).inOrder();
  }

  public void testAsList_toArray_roundTrip() {
    byte[] array = {(byte) 0, (byte) 1, (byte) 2};
    List<Byte> list = Bytes.asList(array);

        return new BiMapEntry(entry);
      }

      @Override
      public void remove() {
        if (entry == null) {
          throw new IllegalStateException("no calls to next() since the last call to remove()");
        }
        V value = entry.getValue();
        iterator.remove();
        removeFromInverseMap(value);
        entry = null;
      }
    };
  }

  @WeakOuter

  }

  public void testLexicographicalComparator() {
    List<short[]> ordered =
        Arrays.asList(
            new short[] {},
            new short[] {LEAST},
            new short[] {LEAST, LEAST},
            new short[] {LEAST, (short) 1},
            new short[] {(short) 1},
            new short[] {(short) 1, LEAST},
            new short[] {GREATEST, GREATEST - (short) 1},

		partsCount := totalSize/partSize + 1
		// Return the part's size
		switch {
		case int64(partIndex) < partsCount:
			currPartSize = partSize
		case int64(partIndex) == partsCount:
			// Size of last part
			currPartSize = totalSize % partSize
		default:
			currPartSize = 0
		}
	}
	return currPartSize, nil

        } else {
          current = current.succ();
        }
        return result;
      }

      @Override
      public void remove() {
        checkState(prevEntry != null, "no calls to next() since the last call to remove()");
        setCount(prevEntry.getElement(), 0);
        prevEntry = null;
      }
    };
  }

  @Override
  Iterator<Entry<E>> descendingEntryIterator() {