for (final CommonPrefix commonPrefix : response.commonPrefixes()) {
                final String dirName = getName(commonPrefix.prefix());
                if (StringUtil.isNotBlank(dirName)) {
                    items.add(new StorageItem(dirName, prefix, true, 0, null, encodeId(commonPrefix.prefix())));
                }
            }

            // Process objects (files)

## 定义 `Form` 参数

创建表单（`Form`）参数的方式与 `Body` 和 `Query` 一样：

{* ../../docs_src/request_forms/tutorial001.py hl[7] *}

例如，OAuth2 规范的 "密码流" 模式规定要通过表单字段发送 `username` 和 `password`。

<abbr title="specification">该规范</abbr>要求字段必须命名为 `username` 和 `password`，并通过表单字段发送，不能用 JSON。

使用 `Form` 可以声明与 `Body` （及 `Query`、`Path`、`Cookie`）相同的元数据和验证。

/// info | 说明

`Form` 是直接继承自 `Body` 的类。

///

/// tip | 提示

  static final class BasicAuthInterceptor implements Interceptor {
    private final String credentials;
    private final String host;

    BasicAuthInterceptor(String host, String username, String password) {
      this.credentials = Credentials.basic(username, password);
      this.host = host;
    }

    @Override public Response intercept(Chain chain) throws IOException {
      Request request = chain.request();

  while [ -h "$PRG" ] ; do
    ls=`ls -ld "$PRG"`
    link=`expr "$ls" : '.*-> \(.*\)$'`
    if expr "$link" : '/.*' > /dev/null; then
      PRG="$link"
    else
      PRG="`dirname "$PRG"`/$link"
    fi
  done

  saveddir=`pwd`

  M2_HOME=`dirname "$PRG"`/..

  # make it fully qualified
  M2_HOME=`cd "$M2_HOME" && pwd`

  cd "$saveddir"
  # echo Using m2 at $M2_HOME
fi

# the __path__ so that "from tensorflow.foo import bar" works.
# We're using bitwise, but there's nothing special about that.
_API_MODULE = _sys.modules[__name__].bitwise
_tf_api_dir = _os.path.dirname(_os.path.dirname(_API_MODULE.__file__))
_current_module = _sys.modules[__name__]

if not hasattr(_current_module, "__path__"):
  __path__ = [_tf_api_dir]
elif _tf_api_dir not in __path__:
  __path__.append(_tf_api_dir)

Но вы не ограничены использованием какой-то конкретной модели данных, класса или типа.

Хотите, чтобы в модели были `id` и `email`, но не было `username`? Пожалуйста. Можно использовать те же инструменты.

Хотите просто `str`? Или просто `dict`? Или напрямую экземпляр класса модели базы данных? Всё работает одинаково.

      return false;
    }
    try {
      Class.forName("com.google.appengine.api.utils.SystemProperty");
    } catch (ClassNotFoundException e) {
      return false;
    }
    try {
      // If the current environment is null, we're not inside AppEngine.
      return Class.forName("com.google.apphosting.api.ApiProxy")
              .getMethod("getCurrentEnvironment")

					<property name="updateCommand">[
					"/usr/sbin/htpasswd",
					"-b",
					"/tmp/test.txt",
					"$USERNAME",
					"$PASSWORD"
					]</property>
					<property name="deleteCommand">[
					"/usr/sbin/htpasswd",
					"-D",
					"/tmp/test.txt",
					"$USERNAME"
					]</property>
					<property name="targetUsers">[
					"admin"
					]</property>
				</component>
			</arg>

  var base: String? = null
  var scheme = ""
  var username = ""
  var password: String? = null
  var host = ""
  var port = ""
  var path = ""
  var query = ""
  var fragment = ""

  fun expectParseFailure() = scheme.isEmpty()

  private operator fun set(
    name: String,
    value: String,
  ) {
    when (name) {
      "s" -> scheme = value
      "u" -> username = value
      "pass" -> password = value

{* ../../docs_src/security/tutorial005_an_py310.py hl[106,108:116] *}

## Проверка `username` и формата данных { #verify-the-username-and-data-shape }

Мы проверяем, что получили `username`, и извлекаем scopes.