return current_user


@app.post("/token")
async def login(form_data: Annotated[OAuth2PasswordRequestForm, Depends()]):
    user_dict = fake_users_db.get(form_data.username)
    if not user_dict:
        raise HTTPException(status_code=400, detail="Incorrect username or password")
    user = UserInDB(**user_dict)
    hashed_password = fake_hash_password(form_data.password)
    if not hashed_password == user.hashed_password:

    password = user_dict["password"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
)
```

#### 由另一個模型內容建立 Pydantic 模型 { #a-pydantic-model-from-the-contents-of-another }

如上例我們從 `user_in.model_dump()` 得到 `user_dict`，以下程式碼：

```Python
user_dict = user_in.model_dump()
UserInDB(**user_dict)
```

等同於：

```Python
UserInDB(**user_in.model_dump())
```

}
```

#### Unpacking a `dict` { #unpacking-a-dict }

If we take a `dict` like `user_dict` and pass it to a function (or class) with `**user_dict`, Python will "unpack" it. It will pass the keys and values of the `user_dict` directly as key-value arguments.

So, continuing with the `user_dict` from above, writing:

```Python
UserInDB(**user_dict)
```

would result in something equivalent to:

```Python
UserInDB(

#### 关于 `**user_dict` { #about-user-dict }

`UserInDB(**user_dict)` 是指：

*直接把 `user_dict` 的键与值当作关键字参数传递，等效于：*

```Python
UserInDB(
    username = user_dict["username"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
    disabled = user_dict["disabled"],
    hashed_password = user_dict["hashed_password"],
)
```

/// info | 信息

#### `**user_dict` について { #about-user-dict }

`UserInDB(**user_dict)` は次を意味します:

`user_dict` のキーと値を、そのままキーワード引数として渡します。つまり次と同等です:

```Python
UserInDB(
    username = user_dict["username"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
    disabled = user_dict["disabled"],
    hashed_password = user_dict["hashed_password"],
)
```

def get_password_hash(password):
    return password_hash.hash(password)


def get_user(db, username: str):
    if username in db:
        user_dict = db[username]
        return UserInDB(**user_dict)


def authenticate_user(fake_db, username: str, password: str):
    user = get_user(fake_db, username)
    if not user:
        verify_password(password, DUMMY_HASH)
        return False

def get_password_hash(password):
    return password_hash.hash(password)


def get_user(db, username: str):
    if username in db:
        user_dict = db[username]
        return UserInDB(**user_dict)


def authenticate_user(fake_db, username: str, password: str):
    user = get_user(fake_db, username)
    if not user:
        verify_password(password, DUMMY_HASH)
        return False

def get_password_hash(password):
    return password_hash.hash(password)


def get_user(db, username: str):
    if username in db:
        user_dict = db[username]
        return UserInDB(**user_dict)


def authenticate_user(fake_db, username: str, password: str):
    user = get_user(fake_db, username)
    if not user:
        verify_password(password, DUMMY_HASH)
        return False

```

#### Desempaquetando un `dict` { #unpacking-a-dict }

Si tomamos un `dict` como `user_dict` y lo pasamos a una función (o clase) con `**user_dict`, Python lo "desempaquetará". Pasará las claves y valores del `user_dict` directamente como argumentos clave-valor.

Así que, continuando con el `user_dict` anterior, escribir:

```Python
UserInDB(**user_dict)
```

sería equivalente a algo como:

```Python
UserInDB(

#### Déballer un `dict` { #unpacking-a-dict }

Si nous prenons un `dict` comme `user_dict` et que nous le passons à une fonction (ou une classe) avec `**user_dict`, Python va « déballer » ce `dict`. Il passera les clés et valeurs de `user_dict` directement comme arguments nommés.

Ainsi, en reprenant `user_dict` ci-dessus, écrire :

```Python
UserInDB(**user_dict)
```

aurait pour résultat quelque chose d'équivalent à :

```Python