* string -- for example, if it requires lookahead or the like. The offset must be
           * increased to look for separators beyond this point, without changing the start position
           * of the next returned substring -- so nextStart stays the same.
           */
          offset++;
          if (offset > toSplit.length()) {
            offset = -1;

     *
     * 1) To invoke FinalizableReference.finalizeReferent()
     *
     * 2) To detect when FinalizableReference's class loader has to be garbage collected, at which
     * point, Finalizer can stop running
     */
    if (!finalizableReferenceClass.getName().equals(FINALIZABLE_REFERENCE)) {
      throw new IllegalArgumentException("Expected " + FINALIZABLE_REFERENCE + ".");
    }

   *   <li>execution will not stop until the task queue is empty.
   *   <li>tasks will begin execution with the thread marked as not interrupted - any interruption
   *       applies only to the task that was running at the point of interruption.
   *   <li>if the thread was interrupted before the SequentialExecutor's worker begins execution,
   *       the interrupt will be restored to the thread after it completes so that its {@code

    /*
     * Sum per-segment modCounts to avoid mis-reporting when elements are concurrently added and
     * removed in one segment while checking another, in which case the table was never actually
     * empty at any point. (The sum ensures accuracy up through at least 1<<31 per-segment
     * modifications before recheck.)  Method containsValue() uses similar constructions for
     * stability checks.
     */
    long sum = 0L;

     * true value. Therefore, we perform at least one Newton iteration to get a guess that's
     * definitely >= floor(sqrt(x)), and then continue the iteration until we reach a fixed point.
     */
    BigInteger sqrt0;
    int log2 = log2(x, FLOOR);
    if (log2 < Double.MAX_EXPONENT) {
      sqrt0 = sqrtApproxWithDoubles(x);
    } else {

        });

    bus.post("hello");

    assertEquals(1, calls.get());
  }

  public void testPrimitiveSubscribeFails() {
    class SubscribesToPrimitive {
      @Subscribe
      public void toInt(int i) {}
    }
    assertThrows(IllegalArgumentException.class, () -> bus.register(new SubscribesToPrimitive()));
  }

  /** Records thrown exception information. */

        });

    bus.post("hello");

    assertEquals(1, calls.get());
  }

  public void testPrimitiveSubscribeFails() {
    class SubscribesToPrimitive {
      @Subscribe
      public void toInt(int i) {}
    }
    assertThrows(IllegalArgumentException.class, () -> bus.register(new SubscribesToPrimitive()));
  }

  /** Records thrown exception information. */

      assertEquals(expected, string);
      if (howManyChecked++ == 5) {
        break;
      }
    }

    // We left the last iterator pointing to "b". But a new iterator should
    // always point to "a".
    for (String string : cycle) {
      assertEquals("a", string);
      break;
    }

    assertEquals("[a, b] (cycled)", cycle.toString());
  }

      expectedInsertions = 1;
    }
    /*
     * TODO(user): Put a warning in the javadoc about tiny fpp values, since the resulting size
     * is proportional to -log(p), but there is not much of a point after all, e.g.
     * optimalM(1000, 0.0000000000000001) = 76680 which is less than 10kb. Who cares!
     */
    long numBits = optimalNumOfBits(expectedInsertions, fpp);

    //     ends up at a[d], which in turn ends up at a[2d], and so on until we get back to a[0].
    //     (All indices taken mod n.) If d and n are mutually prime, all elements will have been
    //     moved at that point. Otherwise, we can rotate the cycle a[1], a[1 + d], a[1 + 2d], etc,
    //     then a[2] etc, and so on until we have rotated all elements. There are gcd(d, n) cycles
    //     in all.