int start = di, ch;
        int strlen = str.length();

        for( int i = 0; di < dlim && i < strlen; i++ ) {
            ch = str.charAt( i );
            if ((ch >= 0x0001) && (ch <= 0x007F)) {
                dst[di++] = (byte)ch;
            } else if (ch > 0x07FF) {
                if((dlim - di) < 3 ) {
                    break;

   * @param lim the limit of bytes to process encoded as a long as big-endian, or -1 to mean the max
   *     limit for numBytes
   */
  @GwtIncompatible // java.nio.charset.Charset
  private static void testBytes(int numBytes, long expectedCount, long start, long lim) {
    byte[] bytes = new byte[numBytes];
    if (lim == -1) {
      lim = 1L << (numBytes * 8);
    }

        int start = di, ch;
        int strlen = str.length();

        for ( int i = 0; di < dlim && i < strlen; i++ ) {
            ch = str.charAt(i);
            if ( ( ch >= 0x0001 ) && ( ch <= 0x007F ) ) {
                dst[ di++ ] = (byte) ch;
            }
            else if ( ch > 0x07FF ) {
                if ( ( dlim - di ) < 3 ) {
                    break;

   * @param lim the limit of bytes to process encoded as a long as big-endian, or -1 to mean the max
   *     limit for numBytes
   */
  @GwtIncompatible // java.nio.charset.Charset
  private static void testBytes(int numBytes, long expectedCount, long start, long lim) {
    byte[] bytes = new byte[numBytes];
    if (lim == -1) {
      lim = 1L << (numBytes * 8);
    }

    void tryClose() {
        synchronized( LOCK ) {

            /* Yes, there is the potential to drop packets
             * because we might close the socket during a
             * request. However the chances are slim and the
             * retry code should ensure the overall request
             * is serviced. The alternative complicates things
             * more than I think is worth it.
             */

        synchronized ( this.LOCK ) {

            /*
             * Yes, there is the potential to drop packets
             * because we might close the socket during a
             * request. However the chances are slim and the
             * retry code should ensure the overall request
             * is serviced. The alternative complicates things
             * more than I think is worth it.
             */