* executor. The listener will have the corresponding transition method called whenever the
   * service changes state. The listener will not have previous state changes replayed, so it is
   * suggested that listeners are added before the service starts.
   *
   * <p>{@code addListener} guarantees execution ordering across calls to a given listener but not

    double[] toDoubleArray() {
      return Arrays.copyOfRange(array, start, end);
    }

    private static final long serialVersionUID = 0;
  }

  /**
   * This is adapted from the regex suggested by {@link Double#valueOf(String)} for prevalidating
   * inputs. All valid inputs must pass this regex, but it's semantically fine if not all inputs

    this.state.markReady();
  }

  /**
   * Registers a {@link Listener} to be {@linkplain Executor#execute executed} on the given
   * executor. The listener will not have previous state changes replayed, so it is suggested that
   * listeners are added before any of the managed services are {@linkplain Service#startAsync
   * started}.
   *
   * <p>{@code addListener} guarantees execution ordering across calls to a given listener but not

   * process in any way, for example being sent over RPC, or saved to disk. For a general-purpose,
   * non-cryptographic hash function that will never change behavior, we suggest {@link
   * #murmur3_128}.
   *
   * <p>Repeated calls to this method on the same loaded {@code Hashing} class, using the same value
   * for {@code minimumBits}, will return identically-behaving {@link HashFunction} instances.

    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned longs, and 0 otherwise. Assumes that x - y fits into a
   * signed long. The implementation is branch-free, and benchmarks suggest it is measurably faster
   * than the straightforward ternary expression.
   */
  @VisibleForTesting
  static int lessThanBranchFree(long x, long y) {
    // Returns the sign bit of x - y.

   * while {@code ImmutableSortedSet.of(s)} returns an {@code ImmutableSortedSet<Set<String>>}
   * containing one element (the given set itself).
   *
   * <p><b>Note:</b> Despite what the method name suggests, if {@code elements} is an {@code
   * ImmutableSortedSet}, it may be returned instead of a copy.
   *
   * <p>This method is not type-safe, as it may be called on elements that are not mutually
   * comparable.
   *

    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned integers, and 0 otherwise. Assumes that x - y fits into
   * a signed int. The implementation is branch-free, and benchmarks suggest it is measurably (if
   * narrowly) faster than the straightforward ternary expression.
   */
  @VisibleForTesting
  static int lessThanBranchFree(int x, int y) {

   * while {@code ImmutableSortedSet.of(s)} returns an {@code ImmutableSortedSet<Set<String>>}
   * containing one element (the given set itself).
   *
   * <p><b>Note:</b> Despite what the method name suggests, if {@code elements} is an {@code
   * ImmutableSortedSet}, it may be returned instead of a copy.
   *
   * <p>This method is not type-safe, as it may be called on elements that are not mutually
   * comparable.
   *

    String leading = ",a,b,c";
    Iterable<String> letters = Splitter.onPattern(",").split(leading);
    assertThat(letters).containsExactly("", "a", "b", "c").inOrder();
  }

  // TODO(kevinb): the name of this method suggests it might not actually be testing what it
  // intends to be testing?
  @GwtIncompatible // Splitter.onPattern
  public void testPatternSplitWithMultipleLetters() {
    Iterable<String> testPatterningMotto =

    String leading = ",a,b,c";
    Iterable<String> letters = Splitter.onPattern(",").split(leading);
    assertThat(letters).containsExactly("", "a", "b", "c").inOrder();
  }

  // TODO(kevinb): the name of this method suggests it might not actually be testing what it
  // intends to be testing?
  @GwtIncompatible // Splitter.onPattern
  public void testPatternSplitWithMultipleLetters() {
    Iterable<String> testPatterningMotto =