return (Multiset<T>) iterable;
  }

  /**
   * Returns a copy of {@code multiset} as an {@link ImmutableMultiset} whose iteration order puts
   * the highest count first, with ties broken by the iteration order of the original multiset.
   *
   * @since 11.0
   */
  public static <E> ImmutableMultiset<E> copyHighestCountFirst(Multiset<E> multiset) {

      K k1, V v1, K k2, V v2, K k3, V v3, K k4, V v4, K k5, V v5) {
    ImmutableSetMultimap.Builder<K, V> builder = ImmutableSetMultimap.builder();
    builder.put(k1, v1);
    builder.put(k2, v2);
    builder.put(k3, v3);
    builder.put(k4, v4);
    builder.put(k5, v5);
    return builder.build();
  }

  // looking for of() with > 5 entries? Use the builder instead.

  /** Returns a new {@link Builder}. */

    HashMultimap<K, V> multimap = HashMultimap.create();
    multimap.put(key, value);
    return multimap;
  }

  @Generates
  static <K, V> LinkedHashMultimap<K, V> generateLinkedHashMultimap(
      @Nullable K key, @Nullable V value) {
    LinkedHashMultimap<K, V> multimap = LinkedHashMultimap.create();
    multimap.put(key, value);
    return multimap;
  }

  @Generates

   *
   * <pre>{@code
   * static final ImmutableSortedMap<Integer, String> INT_TO_WORD =
   *     new ImmutableSortedMap.Builder<Integer, String>(Ordering.natural())
   *         .put(1, "one")
   *         .put(2, "two")
   *         .put(3, "three")
   *         .buildOrThrow();
   * }</pre>
   *
   * <p>For <i>small</i> immutable sorted maps, the {@code ImmutableSortedMap.of()} methods are even
   * more convenient.

            // OK: the method is accessible to us anyway. The setAccessible call is only for
            // unusual execution environments where that might not be true.
          }
          builder.put(method.getName(), method);
        }
      }
      typeVariableMethods = builder.buildKeepingLast();
    }

    private final TypeVariableImpl<?> typeVariableImpl;

   * buildOrThrow() will still throw as if the duplicates had not been eliminated. And the exception
   * message must mention two values that were associated with the duplicate key in two different
   * calls to Builder.put (though we don't really care *which* two values if there were more than
   * two). These considerations lead us to have a field of type DuplicateKey in the Builder, which

     * Builder} and its comparator.
     */
    @Override
    public ImmutableSortedSet<E> build() {
      @SuppressWarnings("unchecked") // we're careful to put only E's in here
      E[] contentsArray = (E[]) contents;
      ImmutableSortedSet<E> result = construct(comparator, size, contentsArray);
      this.size = result.size(); // we eliminated duplicates in-place in contentsArray

   *
   * <p><b>Java 8+ users:</b> If passing a single element {@code e}, the {@code Stream} equivalent
   * of this method is {@code Stream.generate(() -> e)}. Otherwise, put the elements in a collection
   * and use {@code Stream.generate(() -> collection).flatMap(Collection::stream)}.
   */
  @SafeVarargs
  public static <T extends @Nullable Object> Iterable<T> cycle(T... elements) {

     * put more than once, {@link #buildOrThrow} will fail, while {@link #buildKeepingLast} will
     * keep the last value put for that key.
     *
     * @since 11.0
     */
    @CanIgnoreReturnValue
    public Builder<K, V> put(Entry<? extends K, ? extends V> entry) {
      return put(entry.getKey(), entry.getValue());
    }

    /**

    /**
     * Associates the specified range with the specified value.
     *
     * @throws IllegalArgumentException if {@code range} is empty
     */
    @CanIgnoreReturnValue
    public Builder<K, V> put(Range<K> range, V value) {
      checkNotNull(range);
      checkNotNull(value);
      checkArgument(!range.isEmpty(), "Range must not be empty, but was %s", range);
      entries.add(Maps.immutableEntry(range, value));