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docs/zh/docs/advanced/security/http-basic-auth.md
```Python if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"): # Return some error ... ``` 但使用 `secrets.compare_digest()`,可以防御**时差攻击**,更加安全。 ### 时差攻击 什么是**时差攻击**? 假设攻击者试图猜出用户名与密码。 他们发送用户名为 `johndoe`,密码为 `love123` 的请求。 然后,Python 代码执行如下操作: ```Python if "johndoe" == "stanleyjobson" and "love123" == "swordfish":
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docs/de/docs/advanced/security/http-basic-auth.md
Bevorzugen Sie die `Annotated`-Version, falls möglich. ```Python hl_lines="1 11-21" {!> ../../../docs_src/security/tutorial007.py!} ``` Dies wäre das gleiche wie: ```Python if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"): # Einen Error zurückgeben ... ```
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docs/en/docs/advanced/security/http-basic-auth.md
``` === "Python 3.8+ non-Annotated" !!! tip Prefer to use the `Annotated` version if possible. ```Python hl_lines="1 11-21" {!> ../../../docs_src/security/tutorial007.py!} ``` This would be similar to: ```Python if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"): # Return some error ... ```
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docs/em/docs/advanced/security/http-basic-auth.md
⤴️ 🐍 📟 👆 🈸 🔜 🌓 🕳 💖: ```Python if "johndoe" == "stanleyjobson" and "love123" == "swordfish": ... ``` ✋️ ▶️️ 🙍 🐍 🔬 🥇 `j` `johndoe` 🥇 `s` `stanleyjobson`, ⚫️ 🔜 📨 `False`, ↩️ ⚫️ ⏪ 💭 👈 📚 2️⃣ 🎻 🚫 🎏, 💭 👈 "📤 🙅♂ 💪 🗑 🌅 📊 ⚖ 🎂 🔤". & 👆 🈸 🔜 💬 "❌ 👩💻 ⚖️ 🔐". ✋️ ⤴️ 👊 🔄 ⏮️ 🆔 `stanleyjobsox` & 🔐 `love123`. & 👆 🈸 📟 🔨 🕳 💖: ```Python
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