byte[] b2 = "聞朝日新".getBytes(Charsets.US_ASCII);
    byte[] b3 = "????".getBytes(Charsets.US_ASCII);
    byte[] b4 = "ニュース".getBytes(Charsets.US_ASCII);
    byte[] b5 = "スューー".getBytes(Charsets.US_ASCII);
    // Assert they are all equal (using the transitive property)
    assertTrue(Arrays.equals(b1, b2));
    assertTrue(Arrays.equals(b2, b3));
    assertTrue(Arrays.equals(b3, b4));
    assertTrue(Arrays.equals(b4, b5));
  }

    ByteSource b2 = ByteSource.wrap(new byte[0]);
    ByteSource b3 = ByteSource.wrap(new byte[] {4, 5});

    byte[] expected = {0, 1, 2, 3, 4, 5};

    assertArrayEquals(expected, ByteSource.concat(ImmutableList.of(b1, b2, b3)).read());
    assertArrayEquals(expected, ByteSource.concat(b1, b2, b3).read());
    assertArrayEquals(expected, ByteSource.concat(ImmutableList.of(b1, b2, b3).iterator()).read());

    ByteSource b2 = ByteSource.wrap(new byte[0]);
    ByteSource b3 = ByteSource.wrap(new byte[] {4, 5});

    byte[] expected = {0, 1, 2, 3, 4, 5};

    assertArrayEquals(expected, ByteSource.concat(ImmutableList.of(b1, b2, b3)).read());
    assertArrayEquals(expected, ByteSource.concat(b1, b2, b3).read());
    assertArrayEquals(expected, ByteSource.concat(ImmutableList.of(b1, b2, b3).iterator()).read());

    byte[] b2 = "聞朝日新".getBytes(Charsets.US_ASCII);
    byte[] b3 = "????".getBytes(Charsets.US_ASCII);
    byte[] b4 = "ニュース".getBytes(Charsets.US_ASCII);
    byte[] b5 = "スューー".getBytes(Charsets.US_ASCII);
    // Assert they are all equal (using the transitive property)
    assertTrue(Arrays.equals(b1, b2));
    assertTrue(Arrays.equals(b2, b3));
    assertTrue(Arrays.equals(b3, b4));
    assertTrue(Arrays.equals(b4, b5));
  }

 * following three expressions all generate colliding hash codes:
 *
 * <pre>{@code
 * newHasher().putByte(b1).putByte(b2).putByte(b3).hash()
 * newHasher().putByte(b1).putBytes(new byte[] { b2, b3 }).hash()
 * newHasher().putBytes(new byte[] { b1, b2, b3 }).hash()
 * }</pre>
 *
 * <p>If you wish to avoid this, you should either prepend or append the size of each chunk. Keep in

    }

    public void test_toLineString() {
        assertEquals("a1,a2,a3=>b1,b2,b3",
                new SynonymItem(1, new String[] { "a1", "a2", "a3" }, new String[] { "b1", "b2", "b3" }).toLineString());
        assertEquals("a=>b", new SynonymItem(1, new String[] { "a" }, new String[] { "b" }).toLineString());

  @Override
  public int readInt() throws IOException {
    byte b1 = readAndCheckByte();
    byte b2 = readAndCheckByte();
    byte b3 = readAndCheckByte();
    byte b4 = readAndCheckByte();

    return Ints.fromBytes(b4, b3, b2, b1);
  }

  /**
   * Reads a {@code long} as specified by {@link DataInputStream#readLong()}, except using
   * little-endian byte order.
   *

        final byte b2 = DECODE_TABLE[inData.charAt(inIndex + 2)];
        final byte b3 = DECODE_TABLE[inData.charAt(inIndex + 3)];
        outData[outIndex] = (byte) (b0 << 2 & 0xfc | b1 >> 4 & 0x3);
        outData[outIndex + 1] = (byte) (b1 << 4 & 0xf0 | b2 >> 2 & 0xf);
        outData[outIndex + 2] = (byte) (b2 << 6 & 0xc0 | b3 & 0x3f);
    }

   * order; equivalent to {@code Ints.fromByteArray(new byte[] {b1, b2, b3, b4})}.
   *
   * @since 7.0
   */
  public static int fromBytes(byte b1, byte b2, byte b3, byte b4) {
    return b1 << 24 | (b2 & 0xFF) << 16 | (b3 & 0xFF) << 8 | (b4 & 0xFF);
  }

  private static final class IntConverter extends Converter<String, Integer>

    // 1. Subscribers to events posted on different threads can be interleaved with each other
    //    freely. (A event on one thread, B event on another could yield any of
    //    [a1, a2, a3, b1, b2], [a1, b2, a2, a3, b2], [a1, b2, b3, a2, a3], etc.)
    // 2. It's possible for subscribers to actually be dispatched to in a different order than they
    //    were added to the queue. It's easily possible for one thread to take the head of the