for (BigInteger x : POSITIVE_BIGINTEGER_CANDIDATES) {
      int halfEven = BigIntegerMath.log2(x, HALF_EVEN);
      // Now figure out what rounding mode we should behave like (it depends if FLOOR was
      // odd/even).
      boolean floorWasEven = (BigIntegerMath.log2(x, FLOOR) & 1) == 0;
      assertEquals(BigIntegerMath.log2(x, floorWasEven ? HALF_DOWN : HALF_UP), halfEven);
    }
  }

  @GwtIncompatible // TODO

    for (BigInteger x : POSITIVE_BIGINTEGER_CANDIDATES) {
      int halfEven = BigIntegerMath.log2(x, HALF_EVEN);
      // Now figure out what rounding mode we should behave like (it depends if FLOOR was
      // odd/even).
      boolean floorWasEven = (BigIntegerMath.log2(x, FLOOR) & 1) == 0;
      assertEquals(BigIntegerMath.log2(x, floorWasEven ? HALF_DOWN : HALF_UP), halfEven);
    }
  }

  @GwtIncompatible // TODO

    int bTwos = Long.numberOfTrailingZeros(b);
    b >>= bTwos; // divide out all 2s
    while (a != b) { // both a, b are odd
      // The key to the binary GCD algorithm is as follows:
      // Both a and b are odd. Assume a > b; then gcd(a - b, b) = gcd(a, b).
      // But in gcd(a - b, b), a - b is even and b is odd, so we can divide out powers of two.

      // We bend over backwards to avoid branching, adapting a technique from

  public void testEviction_maxWeight_zero() {
    CountingRemovalListener<Integer, Integer> removalListener = countingRemovalListener();
    IdentityLoader<Integer> loader = identityLoader();

    // Even numbers are free, odd are too expensive
    Weigher<Integer, Integer> evensOnly =
        new Weigher<Integer, Integer>() {
          @Override
          public int weigh(Integer k, Integer v) {
            return k % 2;
          }

  //    confusing. It's nice for the finally block to look as close as
  //    possible to the thing right before the try. You could have
  //    guard.leave(), but that's a little odd as well because the
  //    guard doesn't have anything to do with leaving. You can't
  //    really enforce that the guard you're leaving is the same one
  //    you entered with, and it doesn't actually matter.
  //

   * the exception thrown.
   *
   * <p>As we iterate from {@code 0} to {@code nThreads}, threads with an even index will call
   * {@code getUnchecked}, and threads with an odd index will call {@code get}. If the cache throws
   * exceptions, this difference may be visible in the returned List.
   */
  private static <K> List<Object> doConcurrentGet(
      final LoadingCache<K, ?> cache,

boots every Christmas.'

  And she went on planning to herself how she would manage it.
`They must go by the carrier,' she thought; `and how funny it'll
seem, sending presents to one's own feet!  And how odd the
directions will look!

            ALICE'S RIGHT FOOT, ESQ.
                HEARTHRUG,
                    NEAR THE FENDER,
                        (WITH ALICE'S LOVE).

 * not wrapped in {@code ExecutionException}. For just a normal failure, use {@link
 * SettableFuture}).
 *
 * <p>Useful for testing the behavior of Future utilities against odd futures.
 *
 * @author Anthony Zana
 */
@GwtCompatible
final class UncheckedThrowingFuture<V> extends AbstractFuture<V> {

  public static <V> ListenableFuture<V> throwingError(Error error) {

     * We round up if either the fractional part of signif is strictly greater than 0.5 (which is
     * true if the 0.5 bit is set and any lower bit is set), or if the fractional part of signif is
     * >= 0.5 and signifFloor is odd (which is true if both the 0.5 bit and the 1 bit are set).
     */
    boolean increment =
        (twiceSignifFloor & 1) != 0 && ((signifFloor & 1) != 0 || absX.getLowestSetBit() < shift);

    final int s1 = min + (1 * range) / 4;
    final int s2 = min + (2 * range) / 4;
    final int s3 = min + (3 * range) / 4;
    final char[] dst = new char[12];

    // Put surrogate pairs at odd indices so they can be split easily
    dst[0] = 'x';
    Character.toChars(min, dst, 1);
    Character.toChars(s1, dst, 3);
    Character.toChars(s2, dst, 5);
    Character.toChars(s3, dst, 7);