boolean anyOverlaps = false;
      for (Range<Integer> range : subset) {
        boolean overlaps = false;
        for (Range<Integer> other : mutable.asRanges()) {
          if (other.isConnected(range) && !other.intersection(range).isEmpty()) {
            overlaps = true;
            anyOverlaps = true;
            break;
          }
        }

        try {

      boolean anyOverlaps = false;
      for (Range<Integer> range : subset) {
        boolean overlaps = false;
        for (Range<Integer> other : mutable.asRanges()) {
          if (other.isConnected(range) && !other.intersection(range).isEmpty()) {
            overlaps = true;
            anyOverlaps = true;
            break;
          }
        }

        try {

          if (range.isConnected(prevRange) && !range.intersection(prevRange).isEmpty()) {
            throw new IllegalArgumentException(
                "Overlapping ranges: range " + prevRange + " overlaps with entry " + range);
          }
        }
        rangesBuilder.add(range);
        valuesBuilder.add(entries.get(i).getValue());
      }

          if (range.isConnected(prevRange) && !range.intersection(prevRange).isEmpty()) {
            throw new IllegalArgumentException(
                "Overlapping ranges: range " + prevRange + " overlaps with entry " + range);
          }
        }
        rangesBuilder.add(range);
        valuesBuilder.add(entries.get(i).getValue());
      }

      assertThat(expected).hasMessageThat().contains("connected");
    }

    // adjacent below
    assertEquals(Range.closedOpen(4, 4), range.intersection(Range.closedOpen(2, 4)));

    // overlap below
    assertEquals(Range.closed(4, 6), range.intersection(Range.closed(2, 6)));

    // enclosed with same start
    assertEquals(Range.closed(4, 6), range.intersection(Range.closed(4, 6)));

   * Overlapping ranges and empty ranges are forbidden, though adjacent ranges are permitted and
   * will be merged.
   *
   * @throws IllegalArgumentException if any ranges overlap or are empty
   * @since 21.0
   */
  public static <C extends Comparable<?>> ImmutableRangeSet<C> copyOf(Iterable<Range<C>> ranges) {
    return new ImmutableRangeSet.Builder<C>().addAll(ranges).build();
  }

   * Overlapping ranges and empty ranges are forbidden, though adjacent ranges are permitted and
   * will be merged.
   *
   * @throws IllegalArgumentException if any ranges overlap or are empty
   * @since 21.0
   */
  public static <C extends Comparable<?>> ImmutableRangeSet<C> copyOf(Iterable<Range<C>> ranges) {
    return new ImmutableRangeSet.Builder<C>().addAll(ranges).build();
  }

      assertThat(expected).hasMessageThat().contains("connected");
    }

    // adjacent below
    assertEquals(Range.closedOpen(4, 4), range.intersection(Range.closedOpen(2, 4)));

    // overlap below
    assertEquals(Range.closed(4, 6), range.intersection(Range.closed(2, 6)));

    // enclosed with same start
    assertEquals(Range.closed(4, 6), range.intersection(Range.closed(4, 6)));

          }
        } else {
          Set<? extends Entry<? extends E>> entries = multiset.entrySet();
          contents.ensureCapacity(Math.max(contents.size(), entries.size())); // might overlap
          for (Entry<? extends E> entry : multiset.entrySet()) {
            addCopies(entry.getElement(), entry.getCount());
          }
        }
      } else {
        super.addAll(elements);
      }

     * Wrapper<Number>, Wrapper<Integer>, Wrapper<@Nullable Integer>, etc. If we used just
     * Equivalence<? super T> below, no type could satisfy both that bound and T's own
     * bound. With this type, they have some overlap: in our example, Equivalence<Number>
     * and Equivalence<Object>.
     */
    private final Equivalence<? super @NonNull T> equivalence;

    @ParametricNullness private final T reference;