password = user_dict["password"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
)
```

#### 用其它模型中的内容生成 Pydantic 模型

上例中 ，从 `user_in.dict()` 中得到了 `user_dict`，下面的代码：

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

等效于：

```Python
UserInDB(**user_in.dict())
```

⚖️ 🌅 ⚫️❔, ⚙️ `user_dict` 🔗, ⏮️ ⚫️❔ 🎚 ⚫️ 💪 ✔️ 🔮:

```Python
UserInDB(
    username = user_dict["username"],
    password = user_dict["password"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
)
```

#### Pydantic 🏷 ⚪️➡️ 🎚 ➕1️⃣

🖼 🔛 👥 🤚 `user_dict` ⚪️➡️ `user_in.dict()`, 👉 📟:

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

🔜 🌓:

    'full_name': None,
}
```

#### Unwrapping a `dict`

If we take a `dict` like `user_dict` and pass it to a function (or class) with `**user_dict`, Python will "unwrap" it. It will pass the keys and values of the `user_dict` directly as key-value arguments.

So, continuing with the `user_dict` from above, writing:

```Python
UserInDB(**user_dict)
```

would result in something equivalent to:

```Python
UserInDB(

}
```

#### Распаковка `dict`

Если мы возьмём `dict` наподобие `user_dict` и передадим его в функцию (или класс), используя `**user_dict`, Python распакует его. Он передаст ключи и значения `user_dict` напрямую как аргументы типа ключ-значение.

Поэтому, продолжая описанный выше пример с `user_dict`, написание такого кода:

```Python
UserInDB(**user_dict)
```

Будет работать так же, как примерно такой код:

```Python

}
```

#### Desembrulhando um `dict`

Se tomarmos um `dict` como `user_dict` e passarmos para uma função (ou classe) com `**user_dict`, o Python irá "desembrulhá-lo". Ele passará as chaves e valores do `user_dict` diretamente como argumentos chave-valor.

Então, continuando com o `user_dict` acima, escrevendo:

```Python
UserInDB(**user_dict)
```

Resultaria em algo equivalente a:

```Python
UserInDB(

}
```

#### Ein `dict` entpacken

Wenn wir ein `dict` wie `user_dict` nehmen, und es einer Funktion (oder Klassenmethode) mittels `**user_dict` übergeben, wird Python es „entpacken“. Es wird die Schlüssel und Werte von `user_dict` direkt als Schlüsselwort-Argumente übergeben.

Wenn wir also das `user_dict` von oben nehmen und schreiben:

```Python
UserInDB(**user_dict)
```

dann ist das ungefähr äquivalent zu:

```Python

もっと正確に言えば、`user_dict`を将来的にどんな内容であっても直接使用することになります:

```Python
UserInDB(
    username = user_dict["username"],
    password = user_dict["password"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
)
```

#### 別のモデルからつくるPydanticモデル

上述の例では`user_in.dict()`から`user_dict`をこのコードのように取得していますが:

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

これは以下と同等です:

```Python

```

////

#### 🔃 `**user_dict`

`UserInDB(**user_dict)` ⛓:

*🚶‍♀️ 🔑 & 💲 `user_dict` 🔗 🔑-💲 ❌, 🌓:*

```Python
UserInDB(
    username = user_dict["username"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
    disabled = user_dict["disabled"],
    hashed_password = user_dict["hashed_password"],
)
```

/// info

```

////

#### About `**user_dict`

`UserInDB(**user_dict)` means:

*Pass the keys and values of the `user_dict` directly as key-value arguments, equivalent to:*

```Python
UserInDB(
    username = user_dict["username"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
    disabled = user_dict["disabled"],
    hashed_password = user_dict["hashed_password"],
)
```

```

////

#### Über `**user_dict`

`UserInDB(**user_dict)` bedeutet:

*Übergib die Schlüssel und Werte des `user_dict` direkt als Schlüssel-Wert-Argumente, äquivalent zu:*

```Python
UserInDB(
    username = user_dict["username"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
    disabled = user_dict["disabled"],
    hashed_password = user_dict["hashed_password"],