//
    // 1. Subscribers to events posted on different threads can be interleaved with each other
    //    freely. (A event on one thread, B event on another could yield any of
    //    [a1, a2, a3, b1, b2], [a1, b2, a2, a3, b2], [a1, b2, b3, a2, a3], etc.)
    // 2. It's possible for subscribers to actually be dispatched to in a different order than they
    //    were added to the queue. It's easily possible for one thread to take the head of the

    val a3 = "2001:db8::1:0:0:1"
    assertThat(parse("http://[2001:db8:0:0:1:0:0:1]").host).isEqualTo(a3)
    assertThat(parse("http://[2001:0db8:0:0:1:0:0:1]").host).isEqualTo(a3)
    assertThat(parse("http://[2001:db8::1:0:0:1]").host).isEqualTo(a3)
    assertThat(parse("http://[2001:db8::0:1:0:0:1]").host).isEqualTo(a3)
    assertThat(parse("http://[2001:0db8::1:0:0:1]").host).isEqualTo(a3)

        UniAddress a3 = mock(UniAddress.class);
        when(nsc.getAllByName("server", true)).thenReturn(new Address[] { a2, a3 });
        SmbResourceLocatorImpl l3 = locator("smb://server/");
        assertSame(a2, l3.getAddress());
        verify(nsc, times(1)).getAllByName("server", true);
        assertTrue(l3.hasNextAddress());
        assertSame(a3, l3.getNextAddress());

   *     Iterators.peekingIterator(Iterators.forArray("a", "b"));
   * String a1 = peekingIterator.peek(); // returns "a"
   * String a2 = peekingIterator.peek(); // also returns "a"
   * String a3 = peekingIterator.next(); // also returns "a"
   * }
   *
   * <p>Any structural changes to the underlying iteration (aside from those performed by the

	</li>
</ul>

<p>
Given the declarations
</p>

<pre>
type (
	A0 = []string
	A1 = A0
	A2 = struct{ a, b int }
	A3 = int
	A4 = func(A3, float64) *A0
	A5 = func(x int, _ float64) *[]string

	B0 A0
	B1 []string
	B2 struct{ a, b int }
	B3 struct{ a, c int }
	B4 func(int, float64) *B0
	B5 func(x int, y float64) *A1