* the given class. If the object being tested is {@code null} this predicate evaluates to {@code
   * false}.
   *
   * <p>If you want to filter an {@code Iterable} to narrow its type, consider using {@link
   * com.google.common.collect.Iterables#filter(Iterable, Class)} in preference.
   *
   * <p><b>Warning:</b> contrary to the typical assumptions about predicates (as documented at

a",{eras:[{since:"2019-05-01",offset:1,name:"\u4ee4\u548c",narrow:"\u32ff",abbr:"R"},{since:"1989-01-08",until:"2019-04-30",offset:1,name:"\u5e73\u6210",narrow:"\u337b",abbr:"H"},{since:"1926-12-25",until:"1989-01-07",offset:1,name:"\u662d\u548c",narrow:"\u337c",abbr:"S"},{since:"1912-07-30",until:"1926-12-24",offset:1,name:"\u5927\u6b63",narrow:"\u337d",abbr:"T"},{since:"1873-01-01",until:"1912-07-29",offset:6,name:"\u660e\u6cbb",narrow:"\u337e",abbr:"M"},{since:"0001-01-01",until:"1873-12-31",...

    /*
     * Based on Hacker's Delight Fig. 11-5, the two-table-lookup, branch-free implementation.
     *
     * The key idea is that based on the number of leading zeros (equivalently, floor(log2(x))), we
     * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
     * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
     */
    int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];

    // line separator
    assertThat(parse("http://h/\u2028").encodedPath).isEqualTo("/%E2%80%A8")
    // paragraph separator
    assertThat(parse("http://h/\u2029").encodedPath).isEqualTo("/%E2%80%A9")
    // narrow non-breaking space
    assertThat(parse("http://h/\u202f").encodedPath).isEqualTo("/%E2%80%AF")
    // medium mathematical space
    assertThat(parse("http://h/\u205f").encodedPath).isEqualTo("/%E2%81%9F")

2190..21EA    ; valid                  ;      ; NV8    # 1.1  LEFTWARDS ARROW..UPWARDS WHITE ARROW FROM BAR
21EB..21F3    ; valid                  ;      ; NV8    # 3.0  UPWARDS WHITE ARROW ON PEDESTAL..UP DOWN WHITE ARROW
21F4..21FF    ; valid                  ;      ; NV8    # 3.2  RIGHT ARROW WITH SMALL CIRCLE..LEFT RIGHT OPEN-HEADED ARROW
2200..222B    ; valid                  ;      ; NV8    # 1.1  FOR ALL..INTEGRAL

$tooltip-arrow-height ($tooltip-arrow-width * .5) 0;\n      border-top-color: $tooltip-arrow-color;\n    }\n  }\n}\n\n.bs-tooltip-right {\n  padding: 0 $tooltip-arrow-height;\n\n  .arrow {\n    left: 0;\n    width: $tooltip-arrow-height;\n    height: $tooltip-arrow-width;\n\n    &::before {\n      right: 0;\n      border-width: ($tooltip-arrow-width * .5) $tooltip-arrow-height ($tooltip-arrow-width * .5) 0;\n      border-right-color: $tooltip-arrow-color;\n    }\n  }\n}\n\n.bs-tooltip-bottom {\n  padding:...

width: var(--bs-popover-arrow-height);\n  height: var(--bs-popover-arrow-width);\n}\n.bs-popover-end > .popover-arrow::before, .bs-popover-auto[data-popper-placement^=right] > .popover-arrow::before, .bs-popover-end > .popover-arrow::after, .bs-popover-auto[data-popper-placement^=right] > .popover-arrow::after {\n  border-width: calc(var(--bs-popover-arrow-width) * 0.5) var(--bs-popover-arrow-height) calc(var(--bs-popover-arrow-width) * 0.5) 0;\n}\n.bs-popover-end > .popover-arrow::before, .bs-popove...

opover-arrow::before,.bs-popover-end>.popover-arrow::after,.bs-popover-end>.popover-arrow::before{border-width:calc(var(--bs-popover-arrow-width) * .5) var(--bs-popover-arrow-height) calc(var(--bs-popover-arrow-width) * .5) 0}.bs-popover-auto[data-popper-placement^=right]>.popover-arrow::before,.bs-popover-end>.popover-arrow::before{left:0;border-right-color:var(--bs-popover-arrow-border)}.bs-popover-auto[data-popper-placement^=right]>.popover-arrow::after,.bs-popover-end>.popover-arrow::after{l...

72), make([]byte, 72) for i := range a { bufA[i], bufB[i] = a[len(a)-i-1], b[len(b)-i-1] } // Perform a subtraction with borrow. var borrow uint64 for i := 0; i < len(bufA); i += 8 { limbA, limbB := byteorder.LEUint64(bufA[i:]), byteorder.LEUint64(bufB[i:]) _, borrow = bits.Sub64(limbA, limbB, borrow) } // If there is a borrow at the end of the operation, then a < b. return borrow == 1 } golang.org/fips140@v1.0.0/fips140/v1.0.0/ecdh/order_test.go // Copyright 2024 The Go Authors. All rights reserved....

],X=_+b[C],Y=_-b[N],G=m?-H[I]/2:0,K=w===W?B[I]:H[I],Q=w===W?-H[I]:-B[I],Z=t.elements.arrow,$=m&&Z?g(Z):{width:0,height:0},ee=t.modifiersData["arrow#persistent"]?t.modifiersData["arrow#persistent"].padding:{top:0,right:0,bottom:0,left:0},te=ee[C],ne=ee[N],re=de(0,B[I],$[I]),oe=O?B[I]/2-G-re-te-R.mainAxis:K-re-te-R.mainAxis,ie=O?-B[I]/2+G+re+ne+R.mainAxis:Q+re+ne+R.mainAxis,ae=t.elements.arrow&&E(t.elements.arrow),se=ae?"y"===j?ae.clientTop||0:ae.clientLeft||0:0,fe=null!=(q=null==S?void 0:S[j])?q:...