* byte-based hashcode. Otherwise it returns {@link HashCode#asBytes}. Do <i>not</i> mutate this
   * array or else you will break the immutability contract of {@code HashCode}.
   */
  byte[] getBytesInternal() {
    return asBytes();
  }

  /**
   * Returns whether this {@code HashCode} and that {@code HashCode} have the same value, given that

        assertNotNull(result);
    }

    // Test hashCode method
    public void test_hashCode() {
        // Test that hashCode returns consistent value
        int hashCode1 = crawlerEngineClient.hashCode();
        int hashCode2 = crawlerEngineClient.hashCode();
        assertEquals(hashCode1, hashCode2);
    }

    // Test equals method
    public void test_equals() {

    }

    public void test_hashCode() {
        // Test hashCode consistency
        DictionaryExpiredException exception = new DictionaryExpiredException();
        int hashCode1 = exception.hashCode();
        int hashCode2 = exception.hashCode();

        assertEquals(hashCode1, hashCode2);
    }

    public void test_toString() {
        // Test toString method

    Random random = new Random(7);
    List<HashCode> hashCodes = new ArrayList<>();
    for (int i = 0; i < 10; i++) {
      hashCodes.add(HashCode.fromLong(random.nextLong()));
    }
    HashCode hashCode1 = Hashing.combineOrdered(hashCodes);
    Collections.shuffle(hashCodes, random);
    HashCode hashCode2 = Hashing.combineOrdered(hashCodes);

    assertFalse(hashCode1.equals(hashCode2));
  }

    bytesB[4] = (byte) 0xef;

    HashCode hashCodeA = HashCode.fromBytes(bytesA);
    HashCode hashCodeB = HashCode.fromBytes(bytesB);

    // They aren't equal...
    assertFalse(hashCodeA.equals(hashCodeB));

    // But they still have the same Object#hashCode() value.
    // Technically not a violation of the equals/hashCode contract, but...?
    assertEquals(hashCodeA.hashCode(), hashCodeB.hashCode());
  }

      dummy += Objects.hashCode(S0, S1, S2, S3);
    }
    return dummy;
  }

  @Benchmark
  int hashString_5(int reps) {
    int dummy = 0;
    for (int i = 0; i < reps; i++) {
      dummy += Objects.hashCode(S0, S1, S2, S3, S4);
    }
    return dummy;
  }

  @Benchmark
  int hashMixed_5(int reps) {
    int dummy = 0;
    for (int i = 0; i < reps; i++) {
      dummy += Objects.hashCode(I2, S1, D1, S2, I0);

    Random random = new Random(7);
    List<HashCode> hashCodes = new ArrayList<>();
    for (int i = 0; i < 10; i++) {
      hashCodes.add(HashCode.fromLong(random.nextLong()));
    }
    HashCode hashCode1 = Hashing.combineOrdered(hashCodes);
    Collections.shuffle(hashCodes, random);
    HashCode hashCode2 = Hashing.combineOrdered(hashCodes);

    assertFalse(hashCode1.equals(hashCode2));
  }

    bytesB[4] = (byte) 0xef;

    HashCode hashCodeA = HashCode.fromBytes(bytesA);
    HashCode hashCodeB = HashCode.fromBytes(bytesB);

    // They aren't equal...
    assertFalse(hashCodeA.equals(hashCodeB));

    // But they still have the same Object#hashCode() value.
    // Technically not a violation of the equals/hashCode contract, but...?
    assertEquals(hashCodeA.hashCode(), hashCodeB.hashCode());
  }

                .repositories(repositories1)
                .build();

        // Test equals and hashCode
        assertEquals(request1, request2);
        assertEquals(request1.hashCode(), request2.hashCode());
        assertNotEquals(request1, request3);

        // Test toString
        String toString = request1.toString();

        assertEquals("deadbeef", blob.toString(), "toString() should reflect underlying content");
        assertEquals(data.hashCode(), blob.hashCode(), "hashCode should equal the array's hashCode");
    }

    // Validates equals() returns true for same-sized, equal-content blobs
    @Test
    @DisplayName("equals: identical content and size -> true")