};
  }

  /**
   * Returns the element at the specified position in an iterable.
   *
   * <p><b>{@code Stream} equivalent:</b> {@code stream.skip(position).findFirst().get()} (throws
   * {@code NoSuchElementException} if out of bounds)
   *
   * @param position position of the element to return
   * @return the element at the specified position in {@code iterable}

										<div class="col-sm-6">
											<la:message key="labels.storage_tag_value" />
										</div>
									</div>
									<c:forEach var="position" begin="1" end="${savedTags.size()/2}">
									<c:set var="nameKey">name${position}</c:set>
									<c:set var="valueKey">value${position}</c:set>
									<div class="form-group row">
										<div class="col-sm-6">

  margin: 1em;
  min-width: 7em;
}

.user .avatar-wrapper {
  width: 80px;
  height: 80px;
  margin: 10px auto;
  overflow: hidden;
  border-radius: 50%;
  position: relative;
}

.user .avatar-wrapper img {
  position: absolute;
  top: 50%;
  left: 50%;
  transform: translate(-50%, -50%);
}

.user .title {
  text-align: center;
}

.user .count {
  font-size: 80%;

        offset: Annotated[
            int,
            Doc(
                """
                The position in bytes to seek to in the file.
                """
            ),
        ],
    ) -> None:
        """
        Move to a position in the file.

        Any next read or write will be done from that position.

        To be awaitable, compatible with async, this is run in threadpool.
        """

      }
      return crossOverUp(index, x);
    }

    /**
     * Fills the hole at {@code index} by moving in the least of its grandchildren to this position,
     * then recursively filling the new hole created.
     *
     * @return the position of the new hole (where the lowest grandchild moved from, that had no
     *     grandchild to replace it)
     */
    int fillHoleAt(int index) {

      }
      return crossOverUp(index, x);
    }

    /**
     * Fills the hole at {@code index} by moving in the least of its grandchildren to this position,
     * then recursively filling the new hole created.
     *
     * @return the position of the new hole (where the lowest grandchild moved from, that had no
     *     grandchild to replace it)
     */
    int fillHoleAt(int index) {

   * Returns the element at the specified position in this fluent iterable.
   *
   * <p><b>{@code Stream} equivalent:</b> {@code stream.skip(position).findFirst().get()} (but note
   * that this throws different exception types, and throws an exception if {@code null} would be
   * returned).
   *
   * @param position position of the element to return
   * @return the element at the specified position in this fluent iterable

   * Returns the element at the specified position in this fluent iterable.
   *
   * <p><b>{@code Stream} equivalent:</b> {@code stream.skip(position).findFirst().get()} (but note
   * that this throws different exception types, and throws an exception if {@code null} would be
   * returned).
   *
   * @param position position of the element to return
   * @return the element at the specified position in this fluent iterable

      long oldPosition = sourceChannel.position();
      long position = oldPosition;
      long copied;
      do {
        copied = sourceChannel.transferTo(position, ZERO_COPY_CHUNK_SIZE, to);
        position += copied;
        sourceChannel.position(position);
      } while (copied > 0 || position < sourceChannel.size());
      return position - oldPosition;
    }

    background-color: #fafbfc;
    border-bottom: 1px solid #dfe1e6;
}

.card-body.p-0 {
    flex: 1;
    overflow: hidden;
    display: flex;
    flex-direction: column;
    min-height: 0;
    position: relative;
}

/* ============================================
   Empty State (ADS pattern)
   ============================================ */
.empty-state {
    display: flex;
    flex-direction: column;