tests-longest.png...

			}
			if old := b.matchcap[1]; old == -1 || (longest && pos > 0 && pos > old) {
				copy(b.matchcap, b.cap)
			}

			// If going for first match, we're done.
			if !longest {
				return true
			}

			// If we used the entire text, no longer match is possible.
			if pos == b.end {
				return true
			}

			// Otherwise, continue on in hope of a longer match.
			continue
		}
	}

        // We've chosen a connection to evict. Confirm it's still okay to be evicted, then close it.
        toEvict.withLock {
          if (toEvict.calls.isNotEmpty()) return 0L // No longer idle.
          if (toEvict.idleAtNs != toEvictIdleAtNs) return 0L // No longer oldest.
          toEvict.noNewExchanges = true
          connections.remove(toEvict)
        }
        addressStates[toEvict.route.address]?.scheduleOpener()

}

/** Encodes an IPv6 address in canonical form according to RFC 5952. */
internal fun inet6AddressToAscii(address: ByteArray): String {
  // Go through the address looking for the longest run of 0s. Each group is 2-bytes.
  // A run must be longer than one group (section 4.2.2).
  // If there are multiple equal runs, the first one must be used (section 4.2.3).
  var longestRunOffset = -1
  var longestRunLength = 0
  run {

	// This field can be modified by the Longest method,
	// but it is otherwise read-only.
	longest bool // whether regexp prefers leftmost-longest match
}

// String returns the source text used to compile the regular expression.
func (re *Regexp) String() string {
	return re.expr
}

// Copy returns a new [Regexp] object copied from re.
// Calling [Regexp.Longest] on one copy does not affect another.
//

		l[len(l)-1] += "\n\\ No newline at end of file\n"
	}
	return l
}

// tgs returns the pairs of indexes of the longest common subsequence
// of unique lines in x and y, where a unique line is one that appears
// once in x and once in y.
//
// The longest common subsequence algorithm is as described in
// Thomas G. Szymanski, “A Special Case of the Maximal Common

	re.longest = false
	return re.MatchString(text), ""
}

func matchFullLongest(re, refull *Regexp, text string) (bool, string) {
	refull.longest = true
	return refull.MatchString(text), "[full,longest]"
}

func matchPartialLongest(re, refull *Regexp, text string) (bool, string) {
	re.longest = true
	return re.MatchString(text), "[longest]"
}

// Find a handler on a handler map given a path string.
// Most-specific (longest) pattern wins.
func (mux *serveMux121) match(path string) (h Handler, pattern string) {
	// Check for exact match first.
	v, ok := mux.m[path]
	if ok {
		return v.h, v.pattern
	}

	// Check for longest valid match.  mux.es contains all patterns
	// that end in / sorted from longest to shortest.
	for _, e := range mux.es {

	SubKeyCount     uint32
	MaxSubKeyLen    uint32 // size of the key's subkey with the longest name, in Unicode characters, not including the terminating zero byte
	ValueCount      uint32
	MaxValueNameLen uint32 // size of the key's longest value name, in Unicode characters, not including the terminating zero byte
	MaxValueLen     uint32 // longest data component among the key's values, in bytes
	lastWriteTime   syscall.Filetime
}

				return vh
			}
		}
	}
	// prefix match
	var bestMatch *route.VirtualHost
	longest := 0
	for _, vh := range rc.VirtualHosts {
		for _, d := range vh.Domains {
			if d[0] != '*' {
				continue
			}
			if len(host) >= len(d) && strings.HasSuffix(host, d[1:]) && len(d) > longest {
				bestMatch = vh
				longest = len(d)
			}
		}
	}
	if bestMatch != nil {
		return bestMatch
	}